Which of the following is NOT a possible combination of values of the variables in this program when it finishes running?

Find the titles of courses in the Computer Science department that have 3 credits. Find the IDs of all students who were taught

Kay [80]

Answer:

Explanation:

To solve this we break down the question and write the programme in steps as shown in the attachment

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4 0

3 years ago

The first step in the information systems planning process is to ___________.

Basile [38]

Answer: Analyze the organization's strategic plan

Explanation:

The initial step in the information system is to first analyze the strategic plan of the organization so that we can easily identify the main objective and challenge.

It is basically archived by enlisting the particular objective and function in the planning of information system in the organization.

All the remining option are involve in the remaining step of the information system planning not in the initial step.

Therefore, analyze the organization's strategic plan is correct as it is the first step of the information system planning.

7 0

3 years ago

If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support

Molodets [167]

Answer:

Here is the JAVA program. I have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); // create object of Scanner

String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

String LOL = "laughing out loud";

String IDK = "i don't know";

String BFF = "best friends forever";

String IMHO = "in my humble opinion";

String TMI = "too much information";

String TYT = "take your time";

String IDC = "I don't care";

String FYI = "for your information";

String BTW = "by the way";

String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

System.out.println("Input an abbreviation:" + " ");

if(input.hasNext()) { // reads the abbreviation form the user

abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

switch(abbreviation) {

case "LOL" : System.out.println(LOL);

break;

case "IDK" : System.out.println(IDK);

break;

case "BFF" : System.out.println(BFF);

break;

case "IMHO": System.out.println(IMHO);

break;

case "TMI": System.out.println(TMI);

break;

case "TYT": System.out.println(TYT);

break;

case "IDC": System.out.println(IDC);

break;

case "FYI": System.out.println(FYI);

break;

case "BTW": System.out.println(BTW);

break;

case "OMG": System.out.println(OMG);

break;

default : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

5 0

3 years ago

Read 2 more answers

COULD U ANSWER THIS ???

vladimir1956 [14]

Answer:

B.lightning striking a tree

Explanation:

The crowd dispersing in all directions is not a closed-loop by any means, and students jogging around an oval track as well is not a closed-loop, and also not a cross country run from one point to another. However, the lightning striking a tree is a closed loop that best models a circuit. And as lightning strikes the tree, like a closed circuit, tree catches the fire, or in circuitry words, the current is generated, and tree catches the fire due to it, just like bulb starts glowing.

3 0

3 years ago

Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs

marishachu [46]

Answer:

public static String bothStart(String text1, String text2){
String s = "";
if(text1.length() > text2.length()) {
for (int i = 0; i < text2.length(); i++) {
if (text1.charAt(i) == text2.charAt(i)) {
s += text1.charAt(i);
}else{
break;
}
}
return s;
}else{
for (int i = 0; i < text1.length(); i++) {
if (text1.charAt(i) == text2.charAt(i)) {
s += text1.charAt(i);
}else{
break;
}
}
return s;
}
}

Explanation:

Let's start with creating a static method bothStart() with two String type parameters, text1 & text2 (Line 1).

Create a String type variable, s, which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either text1 longer than text2 or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of text1 is longer than text2, the for-loop should only traverse both of strings up to the length of the text2 (Line 5). Within the for-loop, we can use charAt() method to extract individual character from the text1 & text2 and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of text1 .

At the end, return the s as output (Line 21).

5 0

3 years ago