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Lina20 [59]
3 years ago
11

Solve the equation below Explain your steps . Show your math work 2(3x + 4) = 4x + 2

Mathematics
2 answers:
kumpel [21]3 years ago
5 0

Answer:

x= -3

Step-by-step explanation:

2(3x+4)=4x+2 (expand what's in the parentheses)

6x+8=4x+2 (subtract 8)

6x=4x-6 (subtract 4x)

2x = -6 (divide both sides by 2)

x= -3

lisabon 2012 [21]3 years ago
4 0

Answer:

x = -3

Step-by-step explanation:

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3 years ago
When we test Upper H 0​: muequals0 against Upper H Subscript a​: mugreater than​0, we get a​ P-value of 0.03. a. What would the
Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

(c) The null hypothesis will not be rejected. The error is type II error.

Step-by-step explanation:

The hypothesis provided is:

H_{0}: \mu = 0\\ H_{a} : \mu > 0

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

p-value = 0.03 < \alpha  = 0.10

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in​ (a) is an​ error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

p-value = 0.03 > \alpha  = 0.01

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

3 0
3 years ago
HELP HELP !! &amp; PlEASE SHOW WORK ! What would be the compound interest rate if Tom borrowed $6,000 at a 3% interest rate for
In-s [12.5K]

Answer:

Compound interest = $365.4

Step-by-step explanation:

Given:

Amount borrowed = $6,000

Rate of interest = 3%

Number of year =  year

Find:

Compound interest

Computation:

A = P[1+r]ⁿ

Amount after 2 year = 6,000[1 + 3%]²

Amount after 2 year = 6,000[1 + 0.03]²

Amount after 2 year = 6,000[1.03]²

Amount after 2 year = 6,000[1.0609]

Amount after 2 year = 6,365.4

Compound interest = Amount after 2 year - Amount borrowed

Compound interest = 6,365.4 - 6,000

Compound interest = $365.4

3 0
3 years ago
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