Answer:
x = 1
Step-by-step explanation:
![0.3x+1.7=2\\\\0.3x+1.7-1.7=2-1.7\\\\0.3x=0.3\\\\\frac{0.3x=0.3}{0.3}\\\\\boxed{x=1}](https://tex.z-dn.net/?f=0.3x%2B1.7%3D2%5C%5C%5C%5C0.3x%2B1.7-1.7%3D2-1.7%5C%5C%5C%5C0.3x%3D0.3%5C%5C%5C%5C%5Cfrac%7B0.3x%3D0.3%7D%7B0.3%7D%5C%5C%5C%5C%5Cboxed%7Bx%3D1%7D)
Hope this helps.
Answer:
Penperdocular
Step-by-step explanation:
Answer:
y=18
Explanation:
input x=5
rule ——-> 4x-2
=4x5-2
=20-2
=18 {scrutinize}
output y=18
Sam would have to get a 97 on his next test in order to maintain his average score at an 85. This is because if you add up 63, 84, 96, and 97 you get 340. When you divide 340 by the 4 test scores you get an average of exactly 85
Length and width of rectangle is 15 inches and 6 inches respectively
<h3><u>
Solution:</u></h3>
Given that area of a rectangle is 90 square inch
Ratio of length to the width = 5: 2.
Need to determine length and width of rectangle.
As ratio of length to the width is 5 : 2
Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.
<em><u>The formula for area of rectangle is given as:</u></em>
![\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Area%20of%20rectangle%20%7D%3D%5Ctext%20%7B%20length%20of%20rectangle%20%7D%20%5Ctimes%20%5Ctext%20%7B%20width%20of%20rectangle%7D)
Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:
![\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B90%3D5%20x%20%5Ctimes%202%20x%7D%20%5C%5C%5C%5C%20%7B%3D%3E90%3D10%20x%5E%7B2%7D%7D%5Cend%7Barray%7D)
On solving the above expression for x we get
![\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%3D%3E%5Cfrac%7B90%7D%7B10%7D%3Dx%5E%7B2%7D%7D%20%5C%5C%5C%5C%20%7B%3D%3Ex%5E%7B2%7D%3D9%7D%20%5C%5C%5C%5C%20%7B%3D%3Ex%3D%5Csqrt%7B9%7D%3D3%7D%5Cend%7Barray%7D)
![\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20Length%20of%20rectangle%20%7D%3D5%20%5Ctimes%20x%3D5%20%5Ctimes%203%3D15%20%5Ctext%20%7B%20inches%20%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Width%20of%20rectangle%20%7D%3D2%20%5Ctimes%7D%20x%3D2%20%5Ctimes%7D%203%3D6%20%5Ctext%20%7B%20inches%20%7D%7D%5Cend%7Barray%7D)
Hence length and width of rectangle is 15 inches and 6 inches.