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madam [21]
3 years ago
5

38/6 as a mixed number

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0
It is going to be solved like this:

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YOOOO WHO WANNA VAPE WITH ME ????
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Answer:

but  you have to help me

Step-by-step explanation:

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Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16
HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image  PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

|A'B'|=k\times |AB|   .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}

PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}

It is noticed that the size of side in preimage is 2\sqrt{13} and the size of same side in image is \sqrt{13}.

Using equation (1), we get

\sqrt{13}=k \times 2\sqrt{13}

k=\frac{1}{2}

k=0.5

Hence, the value of scale factor is 0.5.

7 0
3 years ago
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a pet shop sells a 6 can multipack of dog food for £3.18 and a 15 can multipack for £7.80. which multipack is the best value for
Annette [7]

Answer:

the 15 multi pack

Step-by-step explanation:

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38° po siya

HOPE IT HELPS

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2 years ago
2x – 1 = y + 4<br>3y +1 = 3х – 2​
ehidna [41]

Answer:x=4 y=3

Step-by-step explanation:

Let's solve your system by substitution.

2x−1=y+4;3y+1=3x−2

Step: Solve2x−1=y+4for y:

2x−1=y+4

2x−1+−y=y+4+−y(Add -y to both sides)

2x−y−1=4

2x−y−1+−2x=4+−2x(Add -2x to both sides)

−y−1=−2x+4

−y−1+1=−2x+4+1(Add 1 to both sides)

−y=−2x+5

−y

−1

=

−2x+5

−1

(Divide both sides by -1)

y=2x−5

Step: Substitute2x−5foryin3y+1=3x−2:

3y+1=3x−2

3(2x−5)+1=3x−2

6x−14=3x−2(Simplify both sides of the equation)

6x−14+−3x=3x−2+−3x(Add -3x to both sides)

3x−14=−2

3x−14+14=−2+14(Add 14 to both sides)

3x=12

3x

3

=

12

3

(Divide both sides by 3)

x=4

Step: Substitute4forxiny=2x−5:

y=2x−5

y=(2)(4)−5

y=3(Simplify both sides of the equation)

3 0
2 years ago
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