Given that the circle radius of 6 cm and a minor arc ST = 11pi/2. the measure of the angle rst can be solve using the formula s = ra
where s is the lenght of the minor arc
r is the radius of the circle
and a is the measure of the angle in radians
s = ra
a = s/r
a = (11pi/2) / 6
a = 11pi/12
or
a = 165 degrees is the measure of angle RST
The cube root of 60 is 3.87 approximately.
Step by step solution:
We can calculate the cube root by Halley's method:
The formula is ![\sqrt[3]{a} = x ((x^{3} + 2a)/(2x^{3} + a))](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%20%3D%20x%20%28%28x%5E%7B3%7D%20%20%2B%202a%29%2F%282x%5E%7B3%7D%20%20%2B%20a%29%29)
where,
a = number whose cube root is being calculated
x = integer guess of its cube root.
Here a = 60,
Suppose x as 3
[∵ 3³ = 27 and 27 is the nearest perfect cube that is less than 60]
⇒ x = 3
Therefore,
∛60 = 3 (3³ + 2 × 60)/(2 × 3³ + 60)) = 3.87
⇒ ∛60 ≈ 3.87
Therefore, the cube root of 60 is 3.87 approximately.
Here , ∛60 is irrational because it cannot be expressed in the form of p/q where q ≠ 0.
Therefore, the value of the cube root of 60 is an irrational number.
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Answer:
15 cm, 15 cm, 11 cm
Step-by-step explanation:
let the equal sides be x then the third side is x - 4
The perimeter is the sum of the 3 sides and is 41 cm , then
x + x + x - 4 = 41
3x - 4 = 41 ( add 4 to both sides )
3x = 45 ( divide both sides by 3 )
x = 15
x - 4 = 15 - 4 = 11
The sides are 15 cm, 15 cm, 11 cm
No it's not possible since absolute value of real number whether positive or negative will always give you a positive real number
The shape of the cross section formed from slicing the pyramid is called; a triangle
<h3>What is the Pyramid's Cross Section? </h3>
We are told that it is a pyramid with a base that is a pentagon with all sides the same length.
Now, the Pyramid's ap-ex is usually constructed by isosceles triangles. Thus, when they are sliced from its ap-ex to from the vertex, in the cross section a triangle will be formed, This triangle will be an isosceles triangle.
In conclusion, the shape of the cross section formed from slicing the pyramid is a triangle.
Read more about pyramid cross section at; brainly.com/question/10076762
