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velikii [3]
4 years ago
6

Consider circle H with a 6 centimeter radius. If the length of minor arc ST is

Mathematics
1 answer:
alexandr402 [8]4 years ago
6 0
Given that the circle radius of 6 cm and a minor arc ST = 11pi/2. the measure of the angle rst can be solve using the formula s = ra
where s is the lenght of the minor arc
r is the radius of the circle 
and a is the measure of the angle in radians
s = ra
a = s/r
a = (11pi/2) / 6
a = 11pi/12 
or
a = 165 degrees is the measure of angle RST
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Alexander is a stockbroker he earns 11% commission each week last week he sold $7,200 worth of stocks how much money did he make
AlekseyPX

Answer:

Last week Alexander earned $792 in commissions.

Step-by-step explanation:

Giving the following information:

Commission= 11%

Sales= $7,200

T<u>o calculate the total commission, we need to use the following formula:</u>

Total commission= commission rate*sales

Total commission= 0.11*7,200

Total commission= $792

Last week Alexander earned $792 in commissions.

3 0
3 years ago
a box with a square base and open top must have a volume of 70304 c m 3 cm3 . we wish to find the dimensions of the box that min
Dmitriy789 [7]

The box should have base 52 cm by 52 cm and height 26 cm.

What is volume?

A three-dimensional space's occupied volume is measured. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.

The Volume of a box with a square base x by x cm and height h cm is

V = x^2h

Since the surface area directly affects the amount of material used, we can reduce the amount of material by reducing the surface area.

The surface area of the box described is  A = x^2 + 4xh

We need A as a function of x alone, so we'll use the fact that

V = x^2h= 70304 cm^3

⇒ h = \frac{70304}{x^2}

So, the area becomes,

A = x^2+4x(\frac{70304}{x^2})\\ A = x^2 + \frac{281216}{x}

We want to minimize A, so

A' = 2x - \frac{281216}{x^2} =0\\\frac{2x^3-281216}{x^2}=0\\ {2x^3-281216} = 0\\x^3 - 140608=0\\x^3 = 140608\\x = 52

The second derivative test verifies that A has a minimum at this critical number:

A'' = 2+\frac{562432}{x^3}  which is positive at x = 52.

Now,

h = \frac{70304}{x^2}= \frac{70304}{(52)^2}=26

Hence, The box should have base 52 cm by 52 cm and height 26 cm.

To know more about volume, click on the link

brainly.com/question/463363

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8 0
2 years ago
-(1+7x)-6(-7-x)=36 what is the answer
pickupchik [31]

Answer:

x = 5

I hope this helps!

8 0
3 years ago
Arturo builds a cube that measures 5 in on each side. What is the volume of Arturo's cube?
crimeas [40]
We know that

[volume of a cube]=b³
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6 0
3 years ago
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Firlakuza [10]

Answer:

i think  students 3

Step-by-step explanation:

7 0
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