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just olya [345]
3 years ago
10

I need help with this question......

Advanced Placement (AP)
2 answers:
Ad libitum [116K]3 years ago
7 0
The correct answer is actually B
Wealthy southerners took advantage of sharecroppers. They were always in debt
Pepsi [2]3 years ago
6 0

Answer:

c

Explanation:

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Use the conversion factors to rewrite the distances in different, but equivalent, units.
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PLEASE HELP ILL MARK BRAINLIEST!!!
tia_tia [17]
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Which of the following is a good rule to remember about placing a semicolon?
WARRIOR [948]

Answer:

D. A semicolon can be used where you might use a period.

Explanation:

A semicolon can be used where you might used a period if the two sentences are related to each other. Also semicolons are used before words such namely, however, therefore. Semicolons are used to join two independent clauses that are similar/closely related to each other especially those joined by a words which are connectors like and, but, or, nor, e.t.c. If a sentence contain many commas, it is suitable to add a semicolon.

7 0
3 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0
3 years ago
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