P(t) = 646*0.66^t . . . . . exponential function for population
p(10) = 646*0.66^10 ≈ 10 . . . population in 10 years
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Answer:
an= 4 . (2)ⁿ⁻¹
an= 3 + 4(n-1)
an = 4+2(n-1)
an = 2 + 3(n-1)
an = 3 . (4)ⁿ⁻¹
a, = 2 · (3)9 - 1
→ an arithmetic sequence with a first term of 2 and a common difference of 3
an = 2 + 3(n-1)
→ a geometric sequence with first term of 4 and a common ratio of 2
an= 4 . (2)ⁿ⁻¹
→ a geometric sequence with first term of 3 and a common ratio of 4
an = 3 . (4)ⁿ⁻¹
→ an arithmetic sequence with a first term of 3 and a common difference of 4
an= 3 + 4(n-1)
:)
Solution :
P(2 states or more | college degree)
![$=\frac{\text{P( 2 states or more and college degree)}}{\text{P(college degree)}}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B%5Ctext%7BP%28%202%20states%20or%20more%20and%20college%20degree%29%7D%7D%7B%5Ctext%7BP%28college%20degree%29%7D%7D%24)
Total number of people = 58
The number of people who lived in two states or more than two states and also have a college degree = 18
Therefore,
![$\text{P(2 states or more states and college degree)} = \frac{18}{58}$](https://tex.z-dn.net/?f=%24%5Ctext%7BP%282%20states%20or%20more%20states%20and%20college%20degree%29%7D%20%3D%20%5Cfrac%7B18%7D%7B58%7D%24)
The number of people who have a college degree = 20
So, ![$\text{P(college degree)} = \frac{20}{58}$](https://tex.z-dn.net/?f=%24%5Ctext%7BP%28college%20degree%29%7D%20%3D%20%5Cfrac%7B20%7D%7B58%7D%24)
Thus,
![$\text{P(2 states or more/college degree)}=\frac{\frac{18}{58}}{\frac{20}{58}}$](https://tex.z-dn.net/?f=%24%5Ctext%7BP%282%20states%20or%20more%2Fcollege%20degree%29%7D%3D%5Cfrac%7B%5Cfrac%7B18%7D%7B58%7D%7D%7B%5Cfrac%7B20%7D%7B58%7D%7D%24)
![$=\frac{18}{20}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B18%7D%7B20%7D%24)
= 0.900
Answer: 2y124√y12
How to: <u>Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.</u>
Have a great day and stay safe !
Answer:
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