What is the value of l-12l

Helppppp pleaseeeeeeeee

notka56 [123]

Answer:

Price 4 years from today: 887

9 years: 1008

just plug in the amount of years for t!

5 0

2 years ago

6x4/12+72/8-9 using pemdas

V125BC [204]

Here ya go ^v^ try to use math.way
I hope this helps
Ya have a wonderful day ^v^

3 0

3 years ago

Read 2 more answers

Can you guys give me a serious answer please?

grin007 [14]

Answer:

800 bacteria

Step-by-step explanation:

Answer of this question depend upon number of hours at the end of day

Let Take Full Day of 24 hrs

Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)

Colby bacteria at end of day = 50 * 2¹²

Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)

Let say Jaquan bacteria at start of Day = J

Jaquan bacteria at end of day = J * 2⁸

Equating Both

J * 2⁸ = 50 * 2¹²

=> J = 50 * 2⁴

=> J = 50 * 16

=> J = 800

Jaquan will start with 800 Bacteria

4 0

2 years ago

A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that

mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, $H_0$ : p = 0.5

Alternate Hypothesis, $H_A$ : p $\neq$ 0.5

(a) The significance level of the test which is represented by $\alpha$ is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

P(Type I error) = $\alpha$

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

$\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0} +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}$ = $\alpha$

$(1\times 1\times 0.5^{10}) +(1 \times 0.5^{10} \times 0.5^{0})$ = $\alpha$

$\alpha$ = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - $\beta$ ).

So, here, X ~ Binom(n = 10, p = 0.1)

$1-\beta$ = P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true)

$1-\beta$ = $\binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0} +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}$

$1-\beta$ = $(1\times 1\times 0.9^{10}) +(1 \times 0.1^{10} \times 0.9^{0})$

$1-\beta$ = 0.3487

Hence, the power of the test is 0.3487.

3 0

3 years ago

Which proportion below has a vertical

creativ13 [48]

Answer:

1 x 6 = 6 and 3 x 6 = 18

Step-by-step explanation:

3 0

3 years ago