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igor_vitrenko [27]
3 years ago
5

PLZ HELPPP.3+28/z +4s use z=7 and s=5

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0
3+28/7+4*5 /reduce the fraction with 7
=> 3+4+20
=> 27
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I have to get this so I pass help plz
pshichka [43]

Answer:

\boxed{\sf x=-2}

\boxed{\sf y=-4}

Step-by-step explanation:

<u>First, Let's  solve for x in -2x+2y=-4:</u>

\sf -2x+2y=-4

<u>Subtract 2y from both sides:</u>

\sf -2x+2y-2y=-4-2y

\sf -2x=-4-2y

<u>Divide both sides by -2:</u>

\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}

\bold{ x=y+2}

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

\sf 3x+3y=-18

→ let x=2+y

\sf 3\bold{(2+y)}+3y=-18

<u>Simplify:</u>

\sf 6+6y=-18

<u>Now, let's solve for y in 6+6y=-18</u>

\sf 6+6y=-18

<u>Subtract 6 from both sides:</u>

\sf 6+6y-6=-18-6

\sf 6y=-24

<u>Divide both sides by 6:</u>

\sf \cfrac{6y}{6}=\cfrac{-24}{6}

\bold{ y=-4}

<u>Now, substitute y=-4 into x=2+y:</u>

\sf x=2+y

→ let y = -4

\sf x=2+\bold{-4}

\bold{x=-2}

Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

5 0
2 years ago
A recursive rule for the arithmetic sequence is a1=-3;an=an-1+7
Shkiper50 [21]
The explicit rule for any arithmetic sequence is:

a(n)=a+d(n-1), a=initial term, d=common difference, n=term number

In this case a=-3 and d=7 so:

a(n)=-3+7(n-1)

a(n)=-3+7n-7

a(n)=7n-10
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Answer:

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Step-by-step explanation:

To simplify the expression you must have to use the distributive property:

(3m + 1)(2)

2 x 3m = 6m

2 x 1 = 2

6m + 2

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The correct answer would be a <u>square</u>

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