Let x=large boxes and y=small boxes.
x+y=110
60x+35y=5100
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You need to cancel out one of the variables to solve for one. Let's cancel out y.
-35(x+y=110)
-35x-35y=-3850
60x+35y=5100
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Add the two equations.
25x=1250
x=50
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Plug in 50 for x into one of the equations to solve for y.
50+y=110
y=60
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50 large boxes
60 small boxes
You didn’t add a picture, so it’s impossible to answer
10 dimes
The $2 are exchanged for 10 dimes and 4 quarters, which make 14 coins total.
Answer:
Equilateral triangle
Step-by-step explanation:
equilateral triangle is a triangle in which all three sides have the same length
Answer: (4, -9)
<u>Step-by-step explanation:</u>
Use elimination method. Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable. <em>I will be eliminating y</em>
6x + y = 15 → 2(6x + y = 15) → 12x + 2y = 30
-7x - 2y = -10 → 1(-7x + 2y = -10) → <u> -7x - 2y = -10</u>
5x = 20
x = 4
Next, replace "x" with "4" into either equation and solve for y.
6(4) + y = 15
24 + y = 15
y = -9
<u>Check:</u>
Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.
-7x - 2y = -10
-7(4) - 2(-9) = -10
-28 - -18 = -10
-28 + 18 = -10
-10 = -10