We'll represent the distance as d and the time as t.
d= 3(t+7) because Gilda is 7 minutes late when travelling 3 mph
d= 4(t-5) because Gilda is 5 minutes early at 4 mph
d= 3t + 21
d= 4t -20
3t +21 =4t -20
41=t
d= 3(41) +21= 144
The distance is 144 miles.
Answer:
i
Step-by-step explanation:
i = 
i^2 = -1
i^3 = -i
i^4 = 1
(Make sure you know your exponent rules)
Answer:
f=3/5x+2/5c
Step-by-step explanation:
5/8 as a decimal would be 0.625. :)
<h3>
Answer: -10</h3>
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Work Shown:
First we need to evaluate f(3)
f(x) = -x^2 + 2x
f(x) = -(x)^2 + 2(x)
f(3) = -(3)^2 + 2(3) ... replace every x with 3; apply PEMDAS to simplify
f(3) = -9 + 6
f(3) = -3
Then we subtract 7 from both sides
f(3) - 7 = -3 - 7
f(3) - 7 = -10
