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3 years ago

. The industrial output of an automobile factory increases by 5% of what it had been in the beginning of

Mathematics

1 answer:

bonufazy [111]3 years ago

6 0

Answer = 92,610

If the factor increases output by 5% yearly than the end output will be 92,610

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A square painting has a side length of 18 inches. What is the area of the painting?

WINSTONCH [101]

Hi! So because all the sides of the square are the same side, you multiple two of the side lengths together, so the area of the painting is 18 x 18 = 324 :) Good luck and do well in school!!!!!!!!

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4 years ago

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Help me please,Thanks

lina2011 [118]

The answer is d.

I that is not the correct answer or you want a further explanation as to how I got that comment or private message me. I hope that helps! :0

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4 years ago

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Using the substitution P=1/x and Q=1/y.

erma4kov [3.2K]

Step-by-step explanation:

$2p + q = 3 \\ p - 5q = 7 \\ \\ multiply \: the \: second \: equation \: by \: 2 \\ 2p - 10q = 14 \\ 2p - 10q - (2p + q) = 14 - 3 \\ 2p - 10q - 2p - q = 11 \\ - 11q = 11 \\ q = - 1 \\ \\ 2p + q = 3 \\ 2p - 1 = 3 \\ 2p = 4 \\ p = 2$

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3 years ago

Pls help ill give extra points

Serjik [45]

Answer:

13x

Step-by-step explanation:

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3 years ago

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Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant

Alex787 [66]

Find the intercepts for both planes.

Plane 1, x + y + 2z = 2:

$y=z=0\implies x=2\implies (2,0,0)$

$x=z=0\implies y=2\implies(0,2,0)$

$x=y=0\implies 2z=2\implies z=1\implies(0,0,1)$

Plane 2, 4x + 4y + z = 8:

$y=z=0\implies4x=8\implies x=2\implies(2,0,0)$

$x=z=0\implies4y=8\impliesy=2\implies(0,2,0)$

$x=y=0\implies z=8\implies(0,0,8)$

Both planes share the same x- and y-intercepts, but the second plane's z-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (x, y)-plane where z = 0, we see the bounded region projects down to the triangle in the first quadrant with legs x = 0, y = 0, and x + y = 2, or y = 2 - x.

So the volume of the region is

$\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx$

$=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}$

3 0

3 years ago