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PIT_PIT [208]
3 years ago
8

https://northeast.schoolobjects.com/eduphoria_webcontrols/attachmentwriter.aspx?orgguid=0cdcd836-79e1-43fd-b1f1-87815cd304ec&amp

;attid=b57be0e4-768f-4f58-b615-ebd56e104099 FIND SQ
Mathematics
1 answer:
Zanzabum3 years ago
5 0

Answer:

Links are never trusted sir

Step-by-step explanation:

copy and paste (●'◡'●)

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Jake, Kim and Lee share some money in the ratio 1 : 3 : 6.
Scrat [10]

Answer:

£27.00

Step-by-step explanation:

3 × £9 = £27 amount Lee gets

3 0
3 years ago
Suppose j varies jointly with g and v, and j=1 when g=4 and v=5. what is j when g=10 and v=9?
Tems11 [23]
J\alpha gv
j=agv where a is a constant of proportionality.
j=1 when g=4 and v=5
1=a*4*5
1=20a
a=1/20
a= 0.05
j=0.05gv
When g=10 and v=9,
j=0.05*10*9
j=0.5*9
j=4.5
4 0
4 years ago
What is the equation of this trend line? Please help ASAP!​
Kruka [31]
8+2x is the answer to to this thanks so much
7 0
3 years ago
Read 2 more answers
Points​ E, D, and H are the midpoints of the sides of ΔTUV. UV=56​, TV=72​, and HD=56. Find HE.
natita [175]
We need a diagram to do this
5 0
3 years ago
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
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