We have the equation y = 12x. And we know the value of x. The value of x is 3.
So, if we replace the x variable with the value of x, then we can solve the equation.
y = 12(3)
y = 36
So, the answer is 36.
5 inch is the width, 8 inch is the length.
Find to scale between the two widths:
10 /5 = 2 the larger photo is 2 times larger,
Multiply the known length by 2:
8 x 2 = 16
The length would be 16
Answer:
5cm^3
Step-by-step explanation: please let me know if that wrong.
This is the concept of algebra, given that ab^4=12 and a^5b^5=7776, the value if a will be found as follows:
ab^4=12
a=12/b^4
also;
a^5=7776/b^5
thus;
a=(7776/b^5)^(1/5)
a=6/b
thus the value of a will be:
6/b=12/b^4
dividing both sides by b we get:
6=12/b^3
multiplying both sides by b^3 we get
6b^3=12
b^3=2
hence;
b=2^(1/3)
7/10 is equivalent to 3.5/5 is one