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Genrish500 [490]
3 years ago
8

3. Determine how many real solutions the quadratic equation has. x2 + 6x + 8

Mathematics
2 answers:
Marat540 [252]3 years ago
6 0
The answer is b two solutions
12345 [234]3 years ago
5 0
B is the correct answer
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Step-by-step explanation:

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State the the roots of y=x^2+8x
Likurg_2 [28]

Answer:

The roots of the given equation are x = 0 and x = -8.

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Factoring/Expanding

Quadratic Equations

  • Solving quadratic equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

y = x² + 8x

<u>Step 2: Find Roots</u>

  1. [Quadratic] Factor:                                                                                          y = x(x + 8)
  2. [Quadratic] Set up [Solve]:                                                                             0 = x(x + 8)
  3. [Quadratic] Define:                                                                                         x = 0, -8

∴ the roots of the quadratic equation y = x² + 8x is equal to 0 and -8.

---

Topic: Algebra I

8 0
3 years ago
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