Answer:
(16π - 32) in²
Step-by-step explanation:
In the picture attached, the circle is shown.
Area of one-quarter of circle = 1/4*Area of a circle = 1/4*π*radius² = 1/4*π*8² = 16π in²
Area of the triangle = 1/2*base*height = 1/2*8*8 = 32 in²
Shaded area = Area of one-quarter of circle - Area of the triangle = (16π - 32) in²
B) 28 percent because it would be 2.8 if you had 7/250
I will solve it using vectors
vector(SR)=(-5,0)
vector(ST)=(-6,-6)area equals half the cross product of these vectors
A = 1/2(30-0)=15 square units
Answer:
Apparent power is 1.413Volt-Amps.
Step-by-step explanation:
We are given that in a parallel circuit,
,R=33kΩ and
=82kΩ.
And we are asked to find apparent power.
Apparent power is the combination of true power and reactive power.
In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.
Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.
True power=
Reactive power=
Hence apparent power=