Joshua made note of all the bicycles and cars he could see parked or locked on a

What is the value of x ?!! Please HELP !!!!!! Will mark BRIANLIEST !!!!!!!!!

Arada [10]

Answer:

81

Step-by-step explanation:

angles of a triangle always equal 180, so 41 +58=99, so subtract that from 180 and the remaining angle is 81

4 0

3 years ago

Read 2 more answers

Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq

AnnyKZ [126]

Answer:

$(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Step-by-step explanation:

Step(i):-

Given that the function

f(x) = $e^{4x} \sqrt{1+e^{2x} }$

Now integrating on both sides, we get

$\int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx$

= $\int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx$

Step(ii):-

Let $1 + e^{2x} = t$

$e^{2x} = t -1$

$2e^{2x}dx = d t$

$e^{2x}dx = \frac{1}{2} d t$

= $\int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx$

= $\int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }$

= $\frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }$

= $\frac{1}{2} \int\limits {(t^{\frac{1}{2} } t^{1} +t^{\frac{1}{2} } ) } \, dx$

$= \frac{1}{2} \int\limits {(t^{\frac{3}{2} } +t^{\frac{1}{2} } ) } \, dx$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C$

= $\frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C$

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Final answer:-

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

3 0

3 years ago

Annual returns on stock of the Mean Corporation are approximately normally distributed with a mean of 13.9% and standard deviati

maw [93]

Answer:

(a) z=-0.59

(b) Joe will invest in Mean Corporation. The probability of getting an annual return grater than 11% is 72.3%.

Step-by-step explanation:

We have a normal distribution for the annual return of the stock.

This distribution has mean of 13.9% and s.d. of 4.9%.

If X=11%, we can calculate its corresponding z-value as:

$z=\frac{X-\mu}{\sigma}= \frac{0.11-0.139}{0.049}= -0.5918$

The z-value is z=-0.5918.

The probabilty of P(X>11%)=P(y>-0.5918) is, by the standarized normal distribution table, equal to 0.723.

As its P(y>-0.5918)=P(X>11%)=0.723 bigger than the 70% threshold, Joe will invest in Mean Corporation.

3 0

3 years ago

Gabriel has these cans of soup in his kitchen cabinet.

butalik [34]

Answer:

the answer is the chese soup has a good chance of being picked but not as good as the chicken soup. there would so 3:2 3 to 2. so if they picked the chese soup the first time then there is not a good chance of the chese soup to be picked again. I hope that helped if not et me know

6 0

3 years ago

Trigonometry problem

Marizza181 [45]

Answer:

9.948

Step-by-step explanation:

Calculated based on 2 given angles and 1 given side.

∠A = 180° - B - C = 0.59341 rad = 34°

a = b·sin(A)/sin(B) = 6.71031

c = b·sin(C)/sin(B) = 9.94845

5 0

3 years ago