Answer: Graph D will be correct graph for the given function.
Explanation:
Given function 
Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.
Moreover, the degree of the function is even thus the end behavior of the function is
, as 
and as 
In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph 
, as and , as .) so, it can not be the graph of given function.
In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph as and as .) so, it can not be the graph of given function.
In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph as and as
.) so, it also can not be the graph of given function.
In graph D it has four root as well as it has the same end behavior as the given function. Also it passes through the point (0,1).
Thus, graph D is the graph of given function.
Answer:
C
Step-by-step explanation:
Answer:c. c is the length of the hypotenuse.
Step-by-step explanation:Example 1. Verify Pythagoras' . 7. The isosceles triangle at the top of the next page has 2 sides of length x cm.
No, it is <u>not</u> a translation. The arrow starts pointing to the right and then points upward. A translation would have the arrow always pointing right the entire time, only that its position would move.
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Problem 2
We can shift the K up 6 units to get what you see in the attached image below
Answer:
3.605 ft is the answer.
Step-by-step explanation:
Applying Pythagoras theorem,
a^2 + b^2 = c^2
2^2 + 3^2 = c^2
4 + 9 = c^2
13 = c^2
3.605 = c
therefore, the answer is 3.605.
:)
