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3 years ago

Can someone help me on this one?

Mathematics

2 answers:

umka21 [38]3 years ago

8 0

Answer:

A. 3/x = 20/100

x=15

B. 3/23 = x/100

300=23x

x=13

C. 3/20 = x/100

x=15

D. 17/x=20/100

x=85

Let me know if you have any other questions

jarptica [38.1K]3 years ago

5 0

Answer:

A=15

B=13??

C=15

D=85

Step-by-step explanation:

B is the only one I'm not sure

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What is 200% of 90? Order from least to greatest? 68% 0.63 13/20

Mandarinka [93]

200% of 90 is 180.

13/20=65/100 so

.63 < 13/20 < 68%

4 0

3 years ago

The curved surface area of a right circular cylinder of height 14 cm is 88 cm².

Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

GIVEN :

As per given question we have provided that :

➣ Height of cylinder = 14 cm
➣ Curved surface area = 88 cm²

$\begin{gathered}\end{gathered}$

TO FIND :

in the provided question we need to find :

➠ Radius of cylinder
➠ Diameter of cylinder

$\begin{gathered}\end{gathered}$

USING FORMULAS :

$\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}$

$\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}$

➛ Csa = Curved surface area
➛ π = 22/7
➛ r = radius
➛ h = height
➛ d = diameter

$\begin{gathered}\end{gathered}$

SOLUTION :

Firstly, finding the radius of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\ \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times \cancel{ 14}}}} \\ \\ \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\ \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{88}{88}}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}$

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\ \\ \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}$