Question

A boat in calm seas travels in a straight line and ends the trip 10 km east and 29 km south of its original position. Find the distance of the trip to the nearest tenth.

Answer 1

A boat in the calm seas travels in a straight lir and ends the trip 22 km west and 53 km nort of its original position. To the nearest tenth of degree , find the direction of the trip. Assume the start is at (0,0 ) The end is at (-22,53 ) . direction =tan^ ^ -1(-53/22)=-67.46 But the angle is in the 2nd Quadrant. So, direction ion = - 67.46 + 180 = 112.54 degree Cheers Stan H.

Answer 2

A boat in the calm seas travels in a straight line and ends the trip 22 km west and 53 km north of its original position. To the nearest tenth of a degree, find the direction of the trip.
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Assume the start is at (0,0)
The end is at (-22,53).
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direction = tan^-1(-53/22) = -67.46
But the angle is in the 2nd Quadrant.
So, direction = -67.46 + 180 = 112.54 degrees
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Cheers,
Stan H.
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