A rectangle has a height of x+ 9 and a width of x^2 + 2x
2 answers:
Answer:
x³ + 11x² + 18x
Step-by-step explanation:
(x² + 2x)(x + 9)
<em>Step 1: Distribute x²+2x into x + 9.</em>
x³ + 2x² + 9x² + 18x
<em>Step 2: Combine like terms.</em>
x³ + 11x² + 18x
The area of this rectangle is x³ + 11x² + 18x.
Answer:
Area= height x width = (x + 9) (x^2 + 2x) = x^3 + 2x^2 + 9x^2 + 18x = x^3 + 11 x^2 + 18x
Step-by-step explanation:
The height is (x + 9) and the width is (x^2 + 2x) and the the area of the rectangle is equal to: Area= height x width = (x + 9) (x^2 + 2x) = x^3 + 2x^2 + 9x^2 + 18x = x^3 + 11 x^2 + 18x
You might be interested in
With what ? what do you need help with
Answer:
Step-by-step explanation:
by using theorem.
eg:- The Base Angle Theorem states that in an isosceles triangle, the angles opposite the congruent sides are congruent.
Answer:
9*((2-1)/9)
or
<u>2</u><u> </u><u>-</u>1
9
<u>2-9</u><u> </u>=<u>-7</u>
9. 9
9× <u>-7</u>
9
=<u>-7</u>
<u>2-</u> <u>3</u>
9. -3
=(1.22222222222)
or
11/9
or
1*(2/9)
Answer:
who's ted?
Step-by-step explanation:
weird!?!
..smh
Answer:
alice is 50 years old
Step-by-step explanation: