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Aliun [14]
3 years ago
5

A system of equations is shown.

Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

x = 1, y = 1

x = 2, y = 4

Step-by-step explanation:

substitution method:

x² = 3x - 2

x² - 3x + 2 = 0

(x - 2)(x - 1) = 0

x = 2

x = 1

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Answer:

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Step-by-step explanation:

y = -9 ------(1)

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9x - 4 (-9) = -9

9x = - 45

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The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

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By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

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Answer:

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Step-by-step explanation:

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