we know that
<u>Part 1) </u>
we know that
side 1=15'-7"
side 2=20'-4"
side 3=26'-2"
To find the total length of three sides sum the three sides
so
total length=side 1+side 2 +side 3
substitute
total length=15'-7"+20'-4"+26'-2"
total length=(15'+20'+26')+(7"+4"+2")
total length=(61')+(13")
remember that
12"=1'
13"=12"+1"=1'+1"
substitute
total length=(61')+(1'+1")
total length=(62')+(1")---------> 62'-1"
therefore
<u>the answer is</u>
the total length of three sides is 62'-1"
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
To get the number at the back, you would need to multiply the number in front by 3 and minus 1.
The answer would be A
Answer:
he will have to pay $650 in the month of june
A...............................................................
