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ivanzaharov [21]
3 years ago
10

A = 2, c = 6, and cos B = 3. Find b

Mathematics
1 answer:
malfutka [58]3 years ago
8 0
Is that all the information you have
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What is the period of the function f(x)=sin(x/3) ?
vitfil [10]
<h3>Answer: 6pi radians</h3>

(this is equivalent to 1080 degrees)

======================================

Explanation:

f(x) = sin(x/3)

is the same as

f(x) = 1*sin( (1/3)(x-0) )+0

and that is in the form

f(x) = A*sin( B(x-C) )+D

The letters A,B,C,D are explained below

A = helps find the amplitude

B = 2pi/T, where T is the period

C = determines phase shift (aka left/right shifting)

D = determines vertical shift = midline

All we care about is the value of B as that is the only thing that is connected to the period T

--------

Compare f(x) = 1*sin( (1/3)(x-0) )+0 with f(x) = A*sin( B(x-C) )+D and we see that B = 1/3, so,

B = 2pi/T

1/3 = 2pi/T

1*T = 3*2pi ... cross multiply

T = 6pi

The period is 6pi radians. This is equivalent to 1080 degrees. To convert from radians to degrees, you multiply by (180/pi).

6 0
3 years ago
A quadratic function y=f(x) is plotted on a graph and the vertex of the resulting parabola is (-6, 4). What is the vertex of the
rjkz [21]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{vertex}{\stackrel{h}{-6}~~,~~\stackrel{k}{4}}\qquad \implies f(x)=a[x-(-6)]^2+4\implies \underline{f(x)=a(x+6)^2+4} \\\\[-0.35em] ~\dotfill

f(x-2)=a[(x-2)+6]^2+4\implies \underline{f(x-2)=a(x+4)^2+4} \\\\\\ f(x-2)-2\implies [a(x+4)^2+4]-2\implies \underline{a(x+4)^2+2=g(x)} \\\\\\ a[x-(\stackrel{h}{-4})]^2\stackrel{k}{+2}=g(x)\qquad \stackrel{vertex}{-4~~,~~2}

7 0
3 years ago
The height
andre [41]

The ball describes a parabola, as you can see in the attached picture. So, the point where the ball strike the ground is the point where the parabola meets the x axis. In fact, the x-axis is the set of points where y=0, which means that the ball has height 0 or -again- it hits the ground.

So, we have to set y=0 in our equation and look for the positive solution. We have

-\dfrac{1}{14}x^2+6x+3=0 \iff x=42\pm\sqrt{1806}

And the positive solution is

42+\sqrt{1806}

So that's the distance from the child where the ball strikes the ground.

6 0
3 years ago
Can somebody please help me with this?????
aniked [119]
-3x +5y =5
-3x + 5y = 5
5y = 5 + 3x
y=5/5 + 3x/5
y=1 + 3x/5

-2x -4y =-48
same as 2x + 4y = 48
 2x + 4 (1 + 3x/5 ) = 48
2x + 4 + 12x/5 = 48
2x +12x/5 = 48-4
10x/5 + 12x/5 =44
22x = 44 times 5 = 220
x = 220/22 =10
x = 10

y = 1 + 3x10/5
y = 1 + 30/5
y = 1 + 6 = 7
y = 7

I believe this is the answer. Hope it helps

4 0
4 years ago
Mrs. Smith earns $3500 a month. She saves $280 a month. Savings is what percent<br> of her income?
Gemiola [76]

Answer:

6 to 8 percent

Step-by-step explanation:

4 0
3 years ago
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