Answer:
The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.
Mean = 
Standard deviation = 
We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)


Z=0
P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5
Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Answer:
Step-by-step explanation:
discriminant = (-24)² - 4(9)(16) = 0, so there are two identical roots.
That eliminates choices 2 and 4.
Quadratic formula
x = [24 ± √(24² – 4·9·16)] / [2·9]
= 24 / 18
= 4/3
9x² - 24x + 16 = 9(x-4/3)² = (3x-4)²
Answer:
2494357888
Step-by-step explanation: