All categories

3 years ago

What methods of charging does John use?

Mathematics

1 answer:

lidiya [134]3 years ago

8 0

Answer: The rod through induction electroscope through friction

Step-by-step explanation:

You might be interested in

What is 16 3/7 - 12 2/5

Lubov Fominskaja [6]

16+3/7-(12+2/5)=16-12+3/7-2/5=4+(3*5-2*7)/35=4+1/35

5 0

3 years ago

Read 2 more answers

Which of the following is equal to 722 grams? A. 0.722 kilogram B. 7,220 kilograms C. 722,000 kilograms D. 7.22 kilograms

erik [133]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What are the values of the plots on the number lines?

Elina [12.6K]

Answer:

14. - 15

Step-by-step explanation:

The first one is located at 14. The second one is located at - 15

8 0

3 years ago

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given indefinite integral:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

Learn more about integration here:

brainly.com/question/27805589

brainly.com/question/27983581

brainly.com/question/27759474

5 0

2 years ago

Find the cartesian equation for the parametric equation x = 2sin x, y = cos x

MaRussiya [10]

In this equation y would equal 4 or it could be 1

8 0

3 years ago