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marissa [1.9K]
3 years ago
7

Need help in proving theorems of square please ASAP ​

Mathematics
1 answer:
lions [1.4K]3 years ago
8 0

Answer:

The length of \overline{JO} is 48.

Step-by-step explanation:

A square is a quadrilateral whose four sides have the same length and four internal angles have the same measure. The sum of measures of internal angles in quadrilaterals equals 360°. Let m\,\angle BOJ = 4\cdot x -6 and BO = 2\cdot x - 8, the value of x is:

4\cdot (4\cdot x - 6) = 360^{\circ}

16\cdot x -24 = 360^{\circ}

16\cdot x = 384^{\circ}

x = 24

And the length of JO is:

JO = BO = 2\cdot x - 8

JO = 40

The length of \overline{JO} is 48.

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#7-9 please help with an explanation,, will mark brainliest
Mandarinka [93]

Answers:

<h2>7. 12</h2><h2>8. -√18</h2><h2>9. √220</h2>

Step-by-step explanation:

To find out which is greater, we must eliminate the radical symbol.

#7

\sqrt{88} = 9.38083151965

9.4 < 12

#8

-\sqrt{18} = -4.24264068712

-4.2 > -6

#9

\sqrt{220} = 14.8323969742

14.5 < 14.8

I'm always happy to help :)

8 0
3 years ago
Does the equation 3(2x−1)+5=6(x+1) have one, none, or an infinite amount of solutions?
EleoNora [17]

Answer: No solutions

Step-by-step explanation: If you solve the problem all the way, you get 0 = 4 which is not valid so there is simply no solution

8 0
2 years ago
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Need help with 17 pre college
Ratling [72]
No because if you plug in 4 for x and 5 for y you get -4 not 36
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2 years ago
How many packs of pencils can you get if there is 1,440 pencils and 6 in each pack
mamaluj [8]

Divide 1440 by 6 to get 240 packs.

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3 years ago
Consider a sequence defined by the recursive rule f(1) = 15; f(n)=f(n - 1) - 6 for n 2. Choose True or
Shkiper50 [21]

Answer:

The second term of the sequence is 8  False ⇒ B

The third term of the sequence is 3  True ⇒ A

The fourth term of the sequence is -3  True ⇒ A

Step-by-step explanation:

The form of the recursive rule is:

f(1) = first term; f(n) = f(n - 1) + d, where

  • f(1) is the first term
  • f(n) is the nth term
  • f(n - 1) is the term before the nth term
  • d is the common difference

∵ f(1) = 15, f(n) = f(n - 1) - 6 for n ≥ 2

∴ The first term = 15

∴ d = -6

let us find the 2nd, 3rd, and 4th terms

∵ n = 2

∴ f(2) = f(1) - 6

∵ f(1) = 15

∴ f(2) = 15 - 6 = 9

∴ The second term is 9

∴ The second term of the sequence is 8  False

∵ n = 3

∴ f(3) = f(2) - 6

∵ f(2) = 9

∴ f(3) = 9 - 6 = 3

∴ The third term is 3

∴ The third term of the sequence is 3 True

∵ n = 4

∴ f(4) = f(3) - 6

∵ f(3) = 3

∴ f(4) = 3 - 6 = -3

∴ The fourth term is -3

∴ The fourth term of the sequence is -3 True

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3 years ago
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