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Natasha_Volkova [10]
3 years ago
8

A chi-square test was conducted to investigate whether there is an association between a person's favorite flavor of ice cream a

nd their favorite toppings. Each of 200 randomly selected customers at an ice cream parlor was asked to pick their favorite flavor from vanilla, chocolate, chocolate chip, or none of these. They were also asked to pick their favorite topping from chocolate sauce, peanuts, crumbled cookies, crushed candies, or none of these. The hypothesis test had a test statistic of 24.97 with an associated p-value of 0.015. If the significance level of the test was a = 0.05, which of the following is the correct decision for this hypothesis test?
A. There is not convincing statistical evidence to suggest an association between favorite ice cream flavor and favorite topping.
B. There is convincing statistical evidence to suggest an association between favorite ice cream flavor and favorite topping.
C. There is convincing statistical evidence to suggest there is not an association between favorite ice cream flavor and favorite topping.
D. There is proof that a person's favorite ice cream topping is dependent on the person's favorite ice cream flavor.
E. There is proof that a person's favorite ice cream topping is independent of the person's favorite ice cream flavor.
Mathematics
2 answers:
defon3 years ago
8 0

Answer:

The answer is definitely B

Step-by-step explanation:

I just did this question on my test.

OleMash [197]3 years ago
5 0

Answer:

B

Step-by-step explanation:

I hope it is correct :)

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A national survey indicated that 50​% of adults conduct their banking online. It also found that 20​% are younger than​ 50, and
Arisa [49]

Answer:

The probability that a person is younger than 50 given that she uses onling banking is 1.5%

Step-by-step explanation:

The survey indicated that 50% of adults conducts their banking online.

P(online banking customers) =1/2

Of the total number of customer that bank online, the survey stated that 20% of them are younger than 50 years.

P(customers younger than 50 yrs) =1/5

Out of the 20% than are younger than 50, we were told that 15% of them conduct online banking.

P(younger than 50 online banking customer) =3/20

Therefore the the probability that a = person is younger than 50 given that she uses online banking is  P = 3/20*1/5*1/2 =17==3/200 = 0.015 =1.5%

The probability that she is younger than 50 does not increase or decrease with additional information, it only makes it clearer.

3 0
4 years ago
Helppp meeee plssss with this pls
Darina [25.2K]
It’s the letter “B” I think
8 0
4 years ago
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Based on the density graph below, what is the probability of a value in the sample space being anywhere from 10 to 25?
kompoz [17]
The answer should be 40% because thats the max the density goes
3 0
3 years ago
Gere has 3 times as many shirts with print patterns as he does shirts in solid colors. He has a total of 16 shirts. How many shi
Tcecarenko [31]

Answer:

He has 12 print patterns shirt

Step-by-step explanation:

Here, we are interested in calculating the number of print colored shirts owned by Gere.

From the question, we are told that he has 3 times shirts with print colors as shirts with solid colors.

This means that if the number of solid colored shirt he has is x, then he has 3x print shirts

The addition of both is 16;

hence;

x + 3x = 16

4x = 16

x = 16/4

x = 4

Since number of print shirts = 3x; this means there are 3 * 4 = 12 print shy

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(3, 6 ) is the answer
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