Answer:
the algebraic expression that represent the quotient of a number & thirty is 30 ÷ a
Step-by-step explanation:
The algebraic expression that represent the quotient of a number & thirty is shown below:
As we know that
Quotient means to divide
So here the quotient is 30
And the other number would be 30 ÷ a
Therefore the algebraic expression that represent the quotient of a number & thirty is 30 ÷ a
Step-by-step explanation:
In the picture.
The answer is <em><u>X = 61°</u></em>
Answer:
Arithmetic
Step-by-step explanation:
Analysis:
1) The graph of function f(x) = √x is on the first quadrant, because the domain is x ≥ 0 and the range is y ≥ 0
2) The first transformation, i.e. the reflection of f(x) over the x axis, leaves the function on the fourth quadrant, because the new image is y = - √x.
3) The second transformation, i.e. the reflection of y = - √x over the y-axis, leaves the function on the third quadrant, because the final image is - √(-x). This is, g(x) = - √(-x).
From that you have, for g(x):
* Domain: negative x-axis ( -x ≥ 0 => x ≤ 0)
* Range: negative y-axis ( - √(-x) ≤ 0 or y ≤ 0).
Answers:
Now let's examine the statements:
<span>A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0
B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0
C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.
D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.
E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.
F)The range of g(x) is all values less than or equal to 0.
TRUE: it was proved above.</span>
Answer:
the answer is A. y = x + 2/7
Step-by-step explanation:
