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3 years ago

Which organism is the most closely related to birds? And why?

Biology

2 answers:

egoroff_w [7]3 years ago

8 0

Answer:

chick

Explanation:

it has feathers and lays eggs

aleksandrvk [35]3 years ago

8 0

Green et al.) Crocodiles are the closest living relatives of the birds, sharing a common ancestor that lived around 240 million years ago and also gave rise to the dinosaurs.

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What is the difference between scarcity and shortage?

bija089 [108]

C. Shortages are temporary while scarcity always exists because there will always be a greater need for limited resources.

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3 years ago

The karyotype for trisomy 21 illustrates an example of a genetic mutation caused by A) insertion. B) inversion. C) crossing over

Katyanochek1 [597]

Trisomy 21, as illustrated by the karyotype, is caused by nondisjunction. This occurs when chromosomes do not separate properly during meiosis.

Answer is D) nondisjunction

7 0

3 years ago

Read 2 more answers

Neurons that carry signals from the cns to skeletal muscles are part of the __________.

Sloan [31]

Motor(efferent) division...............

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4 years ago

I need help with this question ASAP!!

grin007 [14]

Answer: it’s about like lifecycle and stuff

Explanation:

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3 years ago

The death rate per 100,000 for lung cancer is 7 among non-smokers and 71 among smokers. The death rate per 100,000 for coronary

victus00 [196]

Answer:

A) 0.83 for lung cancer and 0.18 for coronary thrombosis.

Explanation:

For the population etiologic fraction due to smoking, we use the formula:

$= \frac{P_s(RR_s-1)}{(1+P_s(RR_s-1))}$

For lung cancer:

Given:

$P_s = 55percent = 0.55$

We first find RRs which is the relative risk of dying from cancer for a smoker compared to a non smoker.

$RR_s = \frac{num of smokers death}{num of non-smokers death}$

$= \frac{71}{7}$

= 10.1429

Therefore population etiologic fraction due to cancer wil be:

$\frac{0.55(10.1429-1)}{1+0.55(10.1429-1)}$

$= \frac{5.029}{6.029}$

= 0.8341

Population etiologic fraction of cancer due to smoking is 0.834

•For coronary thrombosis:

Let's use the formula:

$\frac{P_s}{RR_s-1}{1-P_s(RR_s-1}$

Let's first find the RRs (relative risk of dying from cornary thrombosis for a smoker compared to a non smoker)

$= \frac{599}{422}$

$RR_s = 1.4194$

The population etiologic fraction of cornary thrombosis due to smoking, will be:

$= \frac{0.55(1.4194-1)}{1+0.55(1.4194-1)}$

$= \frac{0.231}{1.231}$

= 0.187

The population etiologic fraction of cornary thrombosis due to smoking is 0.187

Therefore the answer is option (A) 0.83 for lung cancer and 0.18 for coronary thrombosis

3 0

3 years ago