Pascal's triangle up to the 5th iteration is
![\begin{array}{cccccc}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\\1&5&10&10&5&1\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccccc%7D1%5C%5C1%261%5C%5C1%262%261%5C%5C1%263%263%261%5C%5C1%264%266%264%261%5C%5C1%265%2610%2610%265%261%5Cend%7Barray%7D)
This tells us
![(x-2)^5=\boxed{1}x^5(-2)^0+\boxed{5}x^4(-2)^1+\boxed{10}x^3(-2)^2+\boxed{10}x^2(-2)^3+\boxed{5}x^1(-2)^4+\boxed{1}x^0(-2)^5](https://tex.z-dn.net/?f=%28x-2%29%5E5%3D%5Cboxed%7B1%7Dx%5E5%28-2%29%5E0%2B%5Cboxed%7B5%7Dx%5E4%28-2%29%5E1%2B%5Cboxed%7B10%7Dx%5E3%28-2%29%5E2%2B%5Cboxed%7B10%7Dx%5E2%28-2%29%5E3%2B%5Cboxed%7B5%7Dx%5E1%28-2%29%5E4%2B%5Cboxed%7B1%7Dx%5E0%28-2%29%5E5)
so the second term in the expansion is
![5x^4(-2)^1=\boxed{-10x^4}](https://tex.z-dn.net/?f=5x%5E4%28-2%29%5E1%3D%5Cboxed%7B-10x%5E4%7D)
<h3>Answer: B+B+4=26
2B=22
B=11
So then, G=11+4
G=15
Step-by-step explanation:
</h3>
I think your equation is on the paper; it’s 2016 A.D + 544 then you’ll get your answer and which is 2560.
(-1,1)
D0 means starting at the origin of Z in this case, so doing the same thing as always, multiply the scale factor -1/2 to the coordinate of Z giving you (-1,1) and this is the final answer because the origin is (0,0) so doesn’t change anything