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WARRIOR [948]
2 years ago
15

Devon drove at the same speed for 4 hours. He drove a total of 120 miles,

Mathematics
2 answers:
ololo11 [35]2 years ago
3 0
He drove 30 miles in 1 hour
mr Goodwill [35]2 years ago
3 0

Answer: 30

Step-by-step explanation:

Devon drove 30 miles in 1 hour because 120/4 is 30

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What is the following quotient? sqrt6+sqrt11/sqrt5+sqrt3​
Gnoma [55]

Answer:

√30-√18+√55-√33/2

Step-by-step explanation:

What is the following quotient? sqrt6+sqrt11/sqrt5+sqrt3​

Given the expression

√6+√11/√5+√3

Rationalize

√6+√11/√5+√3 × √5-√3/√5-√3

= √30-√18+√55-√33/√25-√9

= √30-√18+√55-√33 /5-3

= √30-√18+√55-√33/2

This gives the required quotient

6 0
3 years ago
Find the value of x round to the nearest tenth
Leto [7]

Answer:

58.6

Step-by-step explanation:

Use the formula c=\sqrt{a^{2}+b^{2}

solving for x (b)

b=\sqrt{c^{2}-a^{2} = \sqrt{61^{2}-17^{2} ≈58.58327

and 58.58327 rounds to 58.6

4 0
3 years ago
-2/3 minus (-4/6)= <br>​
lina2011 [118]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

-  \frac{2}{3}  - ( -  \frac{4}{6} ) =  \\

-  \frac{2}{3}  +  \frac{4}{6}  =  \\

-  \frac{2}{3}  +  \frac{2 \times 2}{2 \times 3}  =  \\

-  \frac{2}{3}   +  \frac{2}{3}  =  0\\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0
3 years ago
Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a
Mice21 [21]

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

 parakeet

- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

 of 67 and 520

* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

 D represented the dog

 P represented the parakeet

- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

 dog only had 22 - 4 = 18 families

- The common part between the circle of the dog and the circle of the

 parakeet only had a families

- The common part between the circle of the cat and the circle of the

 parakeet only had b families

- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

5 0
3 years ago
The larger of two numbers is 7 times the smaller number. Three times the larger number is 7 more than 4 times the smaller number
Juliette [100K]

Let the smaller number be x.

Given, the larger number is 7 times the smaller number.

So, the larger number = 7x.

Given, 3 times the larger number is 7 more than 4 times the smaller number.

So we can write the equation as,

3(7x) = 4(x)+7

3(7x) = 4x+7

21x = 4x+7

Now we have to move 4x to the left side by subtracting 4x from both sides.

21x-4x = 4x-4x+7

21x-4x = 7

17x = 7

To get x, we will divide both sides by 17. We will get,

\frac{17x}{17} = \frac{7}{17}

x = \frac{7}{17}

So the smaller number = \frac{7}{17}

The larger number = 7(\frac{7}{17} ) = \frac{49}{17}

So we have got the required numbers.

Smaller number = \frac{7}{17} and larger number = \frac{49}{17}.

4 0
3 years ago
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