Answer:
plz am so sorry I don't no it
Explanation:
Plz give me brainiest
Answer:
D
Explanation:
Two dimensional array contain both rows and columns. Each row represented one record and each column represent one filed in that record.
for ex: int grades[5][3];
here array grades contains 5 rows and in each row we have 3 columns
if we have grades[i][j] then " i " represents number of rows and j represents the number of columns in that row.
j<grades[i].length represents i=0 to 2[here no of columns are 3, array index starts from 0 to 2]
The Answer is D
Answer:
- import java.util.Scanner;
- public class MealPriceCalculation{
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- System.out.print("Enter meal price: ");
- double meal = input.nextDouble();
- System.out.print("Enter tip: ");
- double tip = input.nextDouble();
-
- calculatePrice(meal,tip);
- calculatePrice(meal,(int)tip);
-
- }
-
- public static void calculatePrice(double meal, double tip){
- System.out.println("Total meal price: $" + (meal + tip) );
- }
-
- public static void calculatePrice(double meal, int tip){
- System.out.println("Total meal price $" + (meal+tip));
- }
- }
Explanation:
The solution code is written in Java.
Overload methods are the methods that share the same name but with different method signature. In this question, we create two overload methods calculatePrice (Line 17-23). One version will accept parameter meal and tip in double type and another will accept parameter meal in double but tip in integer. Both of this method are doing the same job which is just printing the total of meal.
In the main program, create a Scanner object and use it to prompt user to input meal price and tip (Line 6-10). Next call the calculatePrice method for twice. In the first time, pass meal and tip as double type data to calculatePrice method (Line 12). In the second time, pass meal in double but tip in integer to the method. Only the method with parameter list that match the argument data type will be implemented and output the total meal price.
Answer:
returns a different value every time you use it
Explanation: :)
Answer:
11 cycles.
Explanation:
One interesting thing to observe in this is that, there is no data hazard because here in any of the two consecutive instruction, they do not share any common register and hence no collision.
Also assuming each this program starts with address 0, so that condition checking at the end which is "bne $7, $4, 0x040" will not lead to branching which repeats the loop. Which means this sequence of 7 instructions run only once.
Now if there is no pipeline hazard (which is the case here) and there are n instruction with s stages in pipeline with each stage take 1 cycle, then total cycle required to finish the program will be n+(s-1)=n+s-1
Here number of instruction n=7 and in multicycle datapath usually pipeline stages s=5.
Then number of cycles needed to execute this sequence will be = 7 +5 -1 = 11 cycles
