The number in the blank box should be 44 because it said that "3 times x and 4 times y is 44".
You need to multiply the first equation by 3:
3x + 3y = 39.
Then, subtract the first equation from the second equation:
3x - 3x = 0
4y - 3y = y
44 - 39 = 5
Your new equation should look like this: y = 5
Now, substitute y = 5 into the first original equation:
x + 5 = 13
x = 8
Ans. (x, y) = (8, 5)
Answer:
y= 8x+4
Step-by-step explanation: can i have brainliest?
First, let's convert each line to slope-intercept form to better see the slopes.
Isolate the y variable for each equation.
2x + 6y = -12
Subtract 2x from both sides.
6y = -12 - 2x
Divide both sides by 6.
y = -2 - 1/3x
Rearrange.
y = -1/3x - 2
Line b:
2y = 3x - 10
Divide both sides by 2.
y = 1.5x - 5
Line c:
3x - 2y = -4
Add 2y to both sides.
3x = -4 + 2y
Add 4 to both sides.
2y = 3x + 4
Divide both sides by 2.
y = 1.5x + 2
Now, let's compare our new equations:
Line a: y = -1/3x - 2
Line b: y = 1.5x - 5
Line c: y = 1.5x + 2
Now, the rule for parallel and perpendicular lines is as follows:
For two lines to be parallel, they must have equal slopes.
For two lines to be perpendicular, one must have the negative reciprocal of the other.
In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.
However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.
<h3><u>B and C are parallel, no perpendicular lines.</u></h3>
Answer:
So interval notation is with ( and [ where ( is exclusive and [ is inclusive.
Like (1,2) is between 1 and 2 exclusive. [1,2] is between 1 and 2 inclusive. (1,2] is between 1 and 2, 1 exclusive 2 inclusive.
at the point (6,0) you see that the graph goes from above 0 to below 0 (from positive to negative)
The values are positive when x is less than 6 and negative when x is greater than 6.
so the positive interval is
(-infinity, 6)
and with inifinity you always use exclusive
It's that because everything from all the way to the left (-infinity) to 6, is above the x-axis, which means it's positive
using this logic can you do the negative interval?
Answer:
<em>a×</em>
<em>a×_</em>
<em>a×_12 </em>
Step-by-step explanation:
1
_
-6
_
2
6×2=12
a×
_
6
_
2
ax
_12
