Theoretical probability of drawing an 'N' tile?

Help me NOW!!!!!!!!!!!

hichkok12 [17]

Answer:

see below

Step-by-step explanation:

m<Q: 360-68-71-124= 97 degrees

m<Y: 360-95-46-74=145 degrees

m<K: 360-49-89-72=150 degrees

m<R: 360-98-65-69=128 degrees

m<C: 360-77-123-86=74 degrees

m<X: 360-135-105-67=53 degrees

m<T: 360-66-114-92=88 degrees

m<F: 360-146-91-75=48 degrees

3 0

3 years ago

Read 2 more answers

If each quadrilateral below is a parallelogram,find the missing measures.

zhenek [66]

Answer:

Part 1) $MN=31\ units$

Part 2) $KN=45\ units$

Part 3) m∠K=61°

Part 4) m∠L=119°

Part 5) m∠M=61°

Step-by-step explanation:

we know that

In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary

Part 1) Find the side MN

we know that

MN≅KL ----> by opposite sides

we have

$KL=31\ units$

therefore

$MN=31\ units$

Part 2) Find the side KN

we know that

KN≅LM ----> by opposite sides

we have

$LM=45\ units$

therefore

$KN=45\ units$

Part 3) Find the measure of angle K

we know that

m∠K+m∠N=180° ----> by consecutive interior angles

we have

m∠N=119°

substitute

m∠K+119°=180°

m∠K=180°-119°

m∠K=61°

Part 4) Find the measure of angle L

we know that

m∠L≅m∠N ----> by opposite angles

we have

m∠N=119°

therefore

m∠L=119°

Part 5) Find the measure of angle M

we know that

m∠M≅m∠K ----> by opposite angles

we have

m∠K=61°

therefore

m∠M=61°

7 0

4 years ago

What’s the diameter of a circle 5in

Molodets [167]

Answer:

About 1.591 in

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students

Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that , $\text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}$

Then , for section A :

$\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}$

$\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200$

Similarly in Section B, $\text{Sum of scores in sec B}=90\times20=1800$

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz = $\dfrac{\text{Total score}}{\text{Total students}}$

$=\dfrac{3000}{35}=85.7142857143\approx85.7$

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0

3 years ago

In an examination it is required to get 40% of the aggregate marks to pass. A student gets 261 marks and is declared failed by 4

svetoff [14.1K]

The solution to the problem is as follows:

→x− 4% (x) = 261

→x − 4x/100 = 261

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

4 0

3 years ago