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2 years ago

Solve when m = 7 and k = 2 6m- 3k A.30 B.21 C.36 D.35

Mathematics

2 answers:

spin [16.1K]2 years ago

7 0

The answer is C, 36.
6(7) - 3(2)
42 - 6
=36

NARA [144]2 years ago

6 0

Agree with the one at the top it’s 36

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Simplify: x^5. X-^5?

WARRIOR [948]

Answer:

i believe the answer you are looking for is 1?

Step-by-step explanation:

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2 years ago

Solve: 37x + 41y = 70<br>41x + 37y = 86

AysviL [449]

Step-by-step explanation:

37x + 41y = 70 --- R¹

41x + 37y = 86 --- R²

R¹ + R² : 78x + 78y = 156

78(x + y) = 156

x + y = 2 --- R³

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4 0

2 years ago

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Lapatulllka [165]

Answer:

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Step-by-step explanation:

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2 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

2 years ago