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kvasek [131]
3 years ago
7

Solve when m = 7 and k = 2 6m- 3k A.30 B.21 C.36 D.35

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0
The answer is C, 36.
6(7) - 3(2)
42 - 6
=36
NARA [144]3 years ago
6 0
Agree with the one at the top it’s 36
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The probability that Gerald makes a three-point shot in basketball is 20%. For practice, Gerald will regularly
denpristay [2]

count all the dots that are greater than 10. you'll get 6 dots. the question is asking for the dots 10 and fewer there is 40 dots in total so you subtract

40-6= 34

the answer is 34/40

6 0
3 years ago
At what value of x do the graphs of the equations below intersect?
Bogdan [553]

Answer:

Step-by-step explanation:

The intersection is the point where two equations meet. It is calculated by substituting terms into the equations involved. For the given systems of equation, calculations are as follows:

2x - y = 6

y = 2x - 6

We substitute the equation above to the second equation.

5x + 10y = –10

5x + 10( 2x - 6 )= –10

Simplifying, 

5x + 20x - 60 = -10

25x = 50

x = 2

Therefore, the intersection has the value of x equal to 2.

3 0
3 years ago
Read 2 more answers
Plzz help me im giving 12 points
Serggg [28]
This Is very simple.

30m + 50 = 20m + 100

This is the new equation needed to solve for m.
first we must isolate "m".

30m + 50 = 20m + 100
        - 50             - 50

30m = 20m + 50
-20m   -20m

10m = 50

divide both sides by 10 to isolate "m".

m = 5

hope this helps!





3 0
4 years ago
A train is traveling at a constant speed. The table shows the distance the train travels at different times during the trip. How
SpyIntel [72]
The train is traveling at 165 mph

495/3=165
825/5=165
1155/7=165
1485/9=165
8 0
3 years ago
Marcos purchased a sail boat for $56,900. He anticipates each year the boat will decrease in value by 8.1% from the previous yea
Varvara68 [4.7K]

Answer: 56,900\left( 0.919\right)^x

Step-by-step explanation:

Given

Marcos purchased a sailboat for \$56,900

Each year the boat will decrease in value by 8.1\%

After 1 year it is

\Rightarrow 56,900-56,900\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\\

after another year it becomes

\Rightarrow 56,900\left( 1-0.081\right)-56,900\left( 1-0.081\right)\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\cdot \left( 1-0.081\right)\\\Rightarrow 56,900\left( 1-0.081\right)^2

After x years it is

\Rightarrow 56,900\left( 1-0.081\right)^x

\Rightarrow 56,900\left( 0.919\right)^x

5 0
3 years ago
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