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katrin [286]
3 years ago
7

Triangle ABC is formed by two parallel lines and two other intersecting lines. Find the measure of each angle A, B, and of the t

riangle.​

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

<u>A = 61°</u>

<u>B = 72°</u>

<u>C = 47°</u>

Step-by-step explanation:

Well, first of all, we can see that:

61^{\circ}+47^{\circ}+B^{\circ}=180^{\circ}

So, we can find angle B.

B=180^{\circ}-47^{\circ}-61^{\circ}

B=72^{\circ}

Now, we can see to that angle C is just 47°

Finally, we know that the sum of all angles in a triangle is 180°, so we have:

B+A+C=180^{\circ}

A=180^{\circ}-47^{\circ}-72^{\circ}

A=61^{\circ}

I hope it helps you!

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For the function given below, find a formula for the Riemann sum obtained by dividing the interval [0,5] into n equal subinterva
sergij07 [2.7K]

Given

we are given a function

f(x)=x^2+5

over the interval [0,5].

Required

we need to find formula for Riemann sum and calculate area under the curve over [0,5].

Explanation

If we divide interval [a,b] into n equal intervals, then each subinterval has width

\Delta x=\frac{b-a}{n}

and the endpoints are given by

a+k.\Delta x,\text{ for }0\leq k\leq n

For k=0 and k=n, we get

\begin{gathered} x_0=a+0(\frac{b-a}{n})=a \\ x_n=a+n(\frac{b-a}{n})=b \end{gathered}

Each rectangle has width and height as

\Delta x\text{ and }f(x_k)\text{ respectively.}

we sum the areas of all rectangles then take the limit n tends to infinity to get area under the curve:

Area=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)

Here

f(x)=x^2+5\text{ over the interval \lbrack0,5\rbrack}\Delta x=\frac{5-0}{n}=\frac{5}{n}x_k=0+k.\Delta x=\frac{5k}{n}f(x_k)=f(\frac{5k}{n})=(\frac{5k}{n})^2+5=\frac{25k^2}{n^2}+5

Now Area=

\begin{gathered} \lim_{n\to\infty}\sum_{k\mathop{=}1}^n\Delta x.f(x_k)=\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{5}{n}(\frac{25k^2}{n^2}+5) \\ =\lim_{n\to\infty}\sum_{k\mathop{=}1}^n\frac{125k^2}{n^3}+\frac{25}{n} \\ =\lim_{n\to\infty}(\frac{125}{n^3}\sum_{k\mathop{=}1}^nk^2+\frac{25}{n}\sum_{k\mathop{=}1}^n1) \\ =\lim_{n\to\infty}(\frac{125}{n^3}.\frac{1}{6}n(n+1)(2n+1)+\frac{25}{n}n) \\ =\lim_{n\to\infty}(\frac{125(n+1)(2n+1)}{6n^2}+25) \\ =\lim_{n\to\infty}(\frac{125}{6}(1+\frac{1}{n})(2+\frac{1}{n})+25) \\ =\frac{125}{6}\times2+25=66.6 \end{gathered}

So the required area is 66.6 sq units.

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1 year ago
The population of ants in the colony can be represented by the function
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Answer: A or C

Step-by-step explanation:

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you have $120 to donate equally to several charities. Does this situaton represent direct or inverse variation? Explain.
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This situation represents inverse variation.

The difference between direct and inverse variation is in direct variation, as one variable goes up the other does too, while in inverse, as one variable goes up the other falls.

In this case, as you donate to more charities, the amount you donate to each charity falls, because you donate an equal amount. This means it's inverse variation.

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8 0
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