So we are assuming that the three shirts have equal price. Let the price of one shirt be a.
In store A:
the cost is (a+a+a) -(25/100)a=3a-0.25a=2.75a
In store B:
the cost is : a+a+50/100 a =a+a+0.5a=2.5a
In store C:
the cost is
[a-(10/100)a]+[a-(10/100)a]+[a-(10/100)a]=[a-0.1a]+[a-0.1a]+[a-0.1a]
=0.9a+0.9a+0.9a= 2.7a
thus the cost of buying the shirts from stores A, B and C is:
2.75a, 2.5 a and 2.7 a respectively.
the best deal, is buying from store B, where the cost is the lowest: 2.5a.
Answer: store B
Let the <span> normal hourly rate be x
so normal wages = 40x
bonus = 1.5x(52-40) = 18x
total = 40x+18x =58x = $638.
x = $11/hour</span>
hello :
<span> (21)(7)(3x) = (21×7×3)(x) = 441x </span>
Ok so basically it's asking for two numbers that are basically the same except one has a bigger hundreds place. So I'm just going to use a random number.
987,654
and
987,554
Do u see the difference? the second number has 5 in the hundreds place while the first number has 6 in the hundreds name so the first number is bigger.
<u>Given</u>:
The given expression is ![16 x^{8}-1](https://tex.z-dn.net/?f=16%20x%5E%7B8%7D-1)
We need to determine the factor of the given expression.
<u>Factor</u>:
Let us rewrite the given expression.
Thus, we have;
![\left(4 x^{4}\right)^{2}-1^{2}](https://tex.z-dn.net/?f=%5Cleft%284%20x%5E%7B4%7D%5Cright%29%5E%7B2%7D-1%5E%7B2%7D)
Since, the above expression is of the form
, let us apply the identity ![a^2-b^2=(a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29)
Thus, we have;
------ (1)
Now, we shall factor the term ![4x^4-1](https://tex.z-dn.net/?f=4x%5E4-1)
![4x^4-1=(2x^2)^2-1^2](https://tex.z-dn.net/?f=4x%5E4-1%3D%282x%5E2%29%5E2-1%5E2)
![=(2x^2+1)(2x^2-1)](https://tex.z-dn.net/?f=%3D%282x%5E2%2B1%29%282x%5E2-1%29)
Substituting the above expression in equation (1), we have;
![\left(4 x^{4}+1\right)\left(2 x^{2}+1\right)(2x^2-1)](https://tex.z-dn.net/?f=%5Cleft%284%20x%5E%7B4%7D%2B1%5Cright%29%5Cleft%282%20x%5E%7B2%7D%2B1%5Cright%29%282x%5E2-1%29)
Therefore, the factor of the given expression is ![\left(4 x^{4}+1\right)\left(2 x^{2}+1\right)(2x^2-1)](https://tex.z-dn.net/?f=%5Cleft%284%20x%5E%7B4%7D%2B1%5Cright%29%5Cleft%282%20x%5E%7B2%7D%2B1%5Cright%29%282x%5E2-1%29)
Hence, Option B is the correct answer.