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ryzh [129]
2 years ago
15

How do you write 0.8 recurring as a fraction?please can i have an explanation aswell :)

Mathematics
1 answer:
monitta2 years ago
7 0

Answer:

\frac{8}{9}

Step-by-step explanation:

we require 2 equations with the repeating digits placed after the decimal point.

let x = 0.888.. (1) ← multiply both sides by 10

10x = 8.888.. (2)

subtract (1) from (2) thus eliminating the repeating digits

9x = 8 ( divide both sides by 9 )

x = \frac{8}{9}

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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
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The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

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<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

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Initial value in 1980 = x

Final value in 1990 = k

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<em><u>Substituting the values in formula,</u></em>

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