A scientist constructs a graph to show the age structure of the human population of Country Y. The graph is shown here.

For a species with a diploid number of 26, indicate how many chromosomes will be present in the somatic nuclei of individuals th

zhuklara [117]

Answer:

<h2>Haploid=13</h2><h2>triploid=39 </h2><h2>tetraploid=52</h2><h2>trisomic=14 </h2><h2>monosomic=12</h2>

Explanation:

Given;

A species with a diploid number of 26, so 26= 2n ( a diploid cell),

so in haploid condition, chromosome number becomes half (13 in this case). triplod is when 2n + n, and 2n +2n ( tetploid). Trisomy and monosomy is the addition or deletion of a sinlge chromosome of a sinlge set .

Haploid=13, one chromosome from each pair of chromosome set,

triploid=39 (13× 3); diploid+ n( 3n)

tetraploid=52 (13× 4) 4n

trisomic=14 (13+1) ; n+1

monosomic=12 (13-1); n-1

7 0

2 years ago

A drug least likely to produce pharmacological violence would be a drug that made an individual __________. agitated and annoyed

BaLLatris [955]

"<span>sleepy or passive"

A drug that leaves an individual sleepy and passive won't likely lead to any violence. These are called h</span>ypnotic or sedative drugs. These drugs are mostly <span>benzodiazepines. They serve to calm and relax an individual and help in cases of insomnia, anxiety or anaesthesia. These drugs' effect is also dose-dependent which means that the more it is taken, the strongest/longest the effect.</span>

7 0

2 years ago

Which element is necessary to complete the graphic organizer?

weeeeeb [17]

Subordinate clause I just took test

5 0

3 years ago

Read 2 more answers

Marketing myopia refers to a. defining a business in terms of goods rather than the benefits customers seek. b. focusing on deli

Lana71 [14]

Answer: option A) defining a business in terms of goods rather than the benefits customers seek.

Explanation:

As the name implies, myopia, relates to a short-sighted or immediate approach. Marketing myopia explains how a company directs its business activities such as production of goods and services BASED on its own needs rather than considering the demands of the consumers/customers.

This, in turns makes a company appear rigid and unable to respond to market dynamics such as inflation.

8 0

2 years ago

Three linked autosomal loci were studied in smurfs.

cupoosta [38]

Answer:

height -------- color --------- mood

(13.2cM) (14.5cM)

C=0.421

I = 0.579

Explanation:

We have the number of descendants of each phenotype product of the tri-hybrid cross.

Phenotype Number

pink, tall, happy 580

blue, dwarf, gloomy 601

pink, tall, gloomy 113

blue, dwarf, happy 107

blue, tall, happy 8

pink, dwarf, gloomy 6

blue, tall, gloomy 98

pink, dwarf, happy 101

Total number of individuals = 1614 = N

Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to know their order in the chromosome, and to do so, we need to compare the phenotypes of the parental with the ones of the double recombinants. We can recognize the parental in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent. So:

Parental)

Pink, tall, happy 580 individuals

Blue, dwarf, gloomy 601 individuals

Simple recombinant)

Pink Tall Gloomy 113 individuals

Blue, Dwarf, Happy 107 individuals

Blue Tall Gloomy 98 individuals

Pink Dwarf Happy 101 individuals

Double Recombinant)

Blue Tall Happy 8 individuals

Pink Dwarf Gloomy 6 individuals

Comparing them we realize that parental and double recombinant individuals differ in the position of the gene codifying for <u>color</u><u>.</u> They only change in the position of Blue and Pink. This suggests that the position of the color gene is in the middle of the other two genes, height and mood, because in a double recombinant only the central gene changes position in the chromatid.

So, the alphabetic order of the genes is:

---- height ---- color ----- mood ----

Now we will call Region I to the area between Height and Color, and Region II to the area between Color and Mood.

Once established the order of the genes we can calculate distances between them, and we will do it from the central gene to the genes on each side. First We will calculate the recombination frequencies, and we will do it by region. We will call P1 to the recombination frequency between Height and color genes, and P2 to the recombination frequency between color and mood.

P1 = (R + DR) / N

P2 = (R + DR)/ N

Where: R is the number of recombinants in each region (the ones that have an intermediate phenotypic frequency), DR is the number of double recombinants in each region, and N is the total number of individuals. So:

Region I

Tall------ Pink--------happy (Parental) 580 individuals

Dwarf ---Pink------- Happy (Simple Recombinant) 101 individuals

Dwarf--- Pink-------Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Tall ------Blue------- Gloomy (Simple Recombinant) 98 individuals

Tall ----- Blue------- Happy (Double Recombinant) 8 individuals

Region II

Tall------ Pink--------happy (Parental) 580 individuals

Tall-------Pink------- Gloomy (Simple Recombinant) 113 individuals

Dwarf----Pink------- Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Dwarf ----Blue-------Happy (Simple Recombinant) 107 individuals

Tall ----- Blue------- Happy (Double Recombinant) 8 individuals

In each region, the highlighted traits are the ones that suffered recombination.

P1 = (R + DR) / N

P1 = (101+6+98+8)/1614

P1 = 213/1614

P1 = 0.132

P2= = (R + DR) / N

P2 = (113+6+107+8)/1614

P1 = 234/1614

P1 = 0.145

Now, to calculate the recombination frequency between the two extreme genes, height and mood, we can just perform addition or a sum:

P1 + P2= Pt

0.132 + 0.145 = Pt

0.277=Pt

The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which every 100 meiotic products, one results in a recombinant product.

Now we must multiply each recombination frequency by 100 to get the genetic distance in map units:

GD1= P1 x 100 = 0.132 x 100 = 13.2 MU = 13.2 cM

GD2= P2 x 100 = 0.145 x 100 = 14.5 MU = 14.5 cM

GD3=Pt x 100 = 0.277 x 100 = 27.7 MU = 27.7 cM

To calculate the coefficient of coincidence, CC, we must use the next formula:

CC= observed double recombinant frequency/expected double recombinant frequency

Note:

-observed double recombinant frequency=total number of observed double recombinant individuals/total number of individuals

-expected double recombinant frequency: recombination frequency in region I x recombination frequency in region II.

CC= ((6 + 8)/1614)/0.132x0.145

CC=0.008/0.019

CC=0.421

The coefficient of interference, I, is complementary with CC.

I = 1 - CC

I = 1 - 0.421

I = 0.579

8 0

2 years ago