Parenthesis first. 6/8 - 1/2 = 1/4 or 0.25
Now we do 1/4 * 3 = 3/4 or 0.75
Finally, we do 3/4 + 0.25 [1/2] = 5/4 or 1.
Hope this helps! ☺♥
3 times -12
Step-by-step explanation:
It could be this or -12 times 3
Answer with explanation:
For any object having the velocity vector as
the magnitude of velocity is given by
For car 1 the velocity vector is
Therefore
Similarly for car 2 we have
Therefore
Comparing both the values we find that car 1 has the greater speed.
Answer:
AC = 14 sqrt(2) = 19.80
Step-by-step explanation:
Below is the diagram showing you how this has been set up. The figure is a trapezoid which means BC and AD are parallel. AC is a transversal of the parallel lines.
Givens
- <ABC = <ACD
- ABCD is a trapezoid
- BC = 14
- AD = 28
- AC is a transversal of BC and AD
Solution
- <ABC = <ACD Given
- <DAC = <ACB Alternate interior angles.
- ΔACB ≅ΔDAC AA
- <BAC = <ADC Angles of similar triangles are equal
- AC /28 = 14/AC Form a proportion from corresponding sides
- AC*AC = 14 * 28 Cross multiply the proportion. Combine
- AC^2 = 392 Express as prime factors.
- AC^2 = 7*7*2*2*2 Take the square root of both sides
- sqrt(AC)^2 = sqrt(7*7*2*2*2)
- AC = 7*2 * sqrt(2)
- AC = 14 sqrt(2) = 19.80
Answer:
(1) The sample mean of the offers is 70.0
(2) The sample variance of the offers is 68
Step-by-step explanation:
(1) Sample mean = summation of offers ÷ number of offers = (64+72+66+58+78+82) ÷ 6 = 420 ÷ 6 = 70.0 (to one decimal place)
(2) Sample variance = summation (offers - sample mean)^2 ÷ number of offers = [(64-70)^2 + (72-70)^2 + (66-70)^2 + (58-70)^2 + (78-70)^2 + (82-70)^2] ÷ 6 = (36+4+16+144+64+144) ÷ 6 = 408 ÷ 6 = 68