
From any proportion, we get another proportion by inverting the extremes (or the means):

= k
so we have:
2x=3k
2x+y=2k therefore:
3k+y=2k
y= - k
x=


= -

The corect answer is A. -3/2
or:

From any proportion, we get another proportion by inverting the extremes and the means:

We use a property of proportions:

where a, d are extremes and b,c are means and the product of the extremes equals the product of the means (a*d=b*c),
so we have

or

(you can check this also by "the product of the extremes equals the product of the means")



3y = - 2x
Answer:
x = 60°
Step-by-step explanation:
Angles on the circle formed by the same arc are congruent, then
∠ BDC = ∠ BAC = 50°
x = 180° - (70 + 50)° ← sum of angles in triangle = 180°
x = 180° - 120° = 60°
Answer:
That would be the point(-2, -1)
Step-by-step explanation:
The graph rises between (-3, -4) and (-2, -1) then falls as it passes through the last 2 points ( y = -1 goes to y= -5 and then to y = -8 as x values move to the right).
Answer:

Step-by-step explanation:
