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2 years ago

Which of the following equations is equivalent to -2(2 − 2x) = 4 − 8(1 − x) ?

Mathematics

2 answers:

Strike441 [17]2 years ago

8 0

Answer:

0 = 4x

Step-by-step explanation:

-2(2 - 2x) = 4 - 8(1 - x)

-4 + 4x = 4 - 8 + 8x

-4 + 4x = -4 + 8x

-4 + 4 = 8x - 4x

0 = 4x

Sauron [17]2 years ago

3 0

Answer:

0=4x

Step-by-step explanation:

You can read this problem as simplify -2(2-2x)=4-8(1-x), because being equivalent to something can be started with simplification.

So now, on to the simplification now:

-2(2-2x)=4-8(1-x)

Step 1: Open Parantheses -4+4x=4-8+8x

(Remember, two negatives equal a postitive. That's why you get 4x and 8x, not -4x nor -8x.)

Step two: Tidy (Put x's on one side, others on the other.) 4x-8x=4-8+4

(Remember, when you move a number/variable to one side, the negative/positive sign becomes the opposite.)

Step three: Solve -4x=0

Now, be get -4x=0. But then again, if -4x=0, then 4x=0, considering <em>x </em>will be zero.

I hope you liked this explanation! If you have more problems, I'm always free to help.

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How many solutions does the following have?<br> 1x-5y=15<br> -1+5y=-15

zhannawk [14.2K]

So than there are

1x -5y =15
-1x +5y = -15
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so from what result that this system has infinitely many solutions

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3 years ago

What is 100000 times 12

iogann1982 [59]

Answer:

1,200,000

Step-by-step explanation:

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2 years ago

It cost Lori $14 to go to the movies. She bought popcorn for $3.50 and a soda for $2.50. How much was her ticket?

DochEvi [55]

Her ticket was 12.00

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3 years ago

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Please answer this asap

Ymorist [56]

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2 years ago

Jack bought a new car in 2014 for 28,000. If the value of the car decreases by 14% each year, write an exponential model for the

elena55 [62]

Answer:

In 2026 car will have a value of $5,000.

Step-by-step explanation:

We have been given that Jack bought a new car in 2014 for 28,000. If the value of the car decreases by 14% each year.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decay or decrease b is in form (1-r), where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

$14\%=\frac{14}{100}=0.14$

Upon substituting a =28,000 and r=0.14 in exponential decay function we will get,

$y=28,000(1-0.14)^x$ , where x represents number of years after 2014.

Therefore, the function $y=28,000(0.86)^x$ represents the value of car x years after 2014.

To find the number of years it will take to car have the value of $5,000, we will substitute y=5,000 in our function.

$5,000=28,000(0.86)^x$

Let us divide both sides of our equation by 28,000.

$\frac{5,000}{28,000}=\frac{28,000(0.86)^x}{28,000}$

$0.1785714285714286=(0.86)^x$

Let us take natural log of both sides of our equation.

$ln(0.1785714285714286)=ln((0.86)^x)$

Using natural log property $ln(a^b)=b*ln(a)$ we will get,

$ln(0.1785714285714286)=x*ln(0.86)$

$\frac{ln(0.1785714285714286)}{ln(0.86)}=\frac{x*ln(0.86)}{ln(0.86)}$

$\frac{-1.7227665977411033893}{-0.1508228897345836}=x$

$x=11.422447\approx 12$

As in the 12th year after 2014 car will have a value of $5,000, so we will add 12 to 2014 to find the year.

$2014+12=2026$

Therefore, in 2026 car will have a value of $5,000.

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3 years ago

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