Steve payed $4 in tax because 10% of 40 is 4. Steve payed $44 in total because 4+40=44.
The formula of the present value of annuity due:
![PV=C*[\frac{1-(1+i)^{-n}}{i}]*(1+i)](https://tex.z-dn.net/?f=PV%3DC%2A%5B%5Cfrac%7B1-%281%2Bi%29%5E%7B-n%7D%7D%7Bi%7D%5D%2A%281%2Bi%29)
For your case:
C = $3000
i = 12% / 100 = 0.12
n = 3 * 2 = 6 (semiannually for 3 years means 6 payments)
So, the solution is:
![PV=3000*[\frac{1-(1+0.12)^{-6}}{0.12}]*(1+0.12)=3000*[\frac{1-0.5066}{0.12}]*1.12=](https://tex.z-dn.net/?f=PV%3D3000%2A%5B%5Cfrac%7B1-%281%2B0.12%29%5E%7B-6%7D%7D%7B0.12%7D%5D%2A%281%2B0.12%29%3D3000%2A%5B%5Cfrac%7B1-0.5066%7D%7B0.12%7D%5D%2A1.12%3D)
2 hours = 45 pages
1 hour = 45 ÷ 2 = 22.5 pages
12 hours = 22.5 x 12 = 270 pages
Answer; 270 pages
Segment BD equals 12<span />
Answer:
a) 0.4770
b) 3.9945
c) z-statistics seem a large value
Step-by-step explanation:
<u>a. Find the standard deviation of the sample proportion based on the null hypothesis</u>
Based on the null hypothesis:
: 0.35
and the standard deviation σ =
=
≈0.4770
<u>b. Find the z statistic</u>
z-statistic is calculated as follows:
z=
where
- X is the proportion of employees in the survey who take advantage of the Credit Union (
)
is the proportion in null hypothesis (0.35)- s is the standard deviation (0.4770)
- N is the sample size (300)
putting the numbers in the formula:
z=
= 3.9945
<u>c. Does the z statistic seem like a particularly large or small value?</u>
z-statistics seem a large value, which will cause us to reject the null hypothesis.