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romanna [79]
3 years ago
10

How many edges does a solid with 11 faces and 11 vertices have?

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

20

Step-by-step explanation:

Given: F = 11, C = 11, E=?

By Euler's formula, we have:

F + V - E = 2 \\  \therefore \: 11 + 11 - E = 2 \\  \therefore \:22 -  E = 2 \\  \therefore \:22 -  2 = E  \\  \huge \red{ \boxed{\therefore \: E = 20}}

Hence, the solid will have 20 edges.

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The tree is 820 inches tall using the similarity of triangles.

To get the height of the tree, we will use the properties of similar triangles expressed as:

\frac{70in}{7ft} = \frac{h}{75ft+7ft}\\\frac{70in}{7ft} = \frac{h}{82ft}\\

  • Note that 1 foot = 12inches
  • 7ft = 84in and 82ft = 984in

  • h is the required height of the tree. Simplify the equation above to get the height "h" and replace feet with inches;

\frac{70}{84} = \frac{h}{984}\\84h =70 \times 984\\84h = 68,880\\h=\frac{68,880}{84}\\h= 820in

Hence the tree is 820 inches tall using the similarity of triangles.

Learn more on similarities of triangles here: brainly.com/question/24295402

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