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Xelga [282]
3 years ago
6

How many complex numbers have modulus of 5?

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
5 0

Answer:

Infinite

Step-by-step explanation:

Murrr4er [49]3 years ago
3 0

Answer:

12 complex numbers

So 12 complex numbers have modulus 5.

Step-by-step explanation:

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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
EleoNora [17]

Answer:

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Step-by-step explanation:

The given function is:

g(y) = \frac{y-5}{y^2-3y+15}

According to the quotient rule:

d(\frac{f(y)}{h(y)})  = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}

Applying the quotient rule:

g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}

The values for which g'(y) are zero are the critical points:

g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10

The critical values are y = 0 and y = 10.

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svetoff [14.1K]

Answer:

2z+6

Step-by-step explanation:

z+z+6

Combine like terms

2z+6

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3 years ago
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