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3 years ago

Please help!!!!!!!!!! X= Y=

Mathematics

1 answer:

Keith_Richards [23]3 years ago

3 0

Answer:

X= 5.5

Y= 7.4666

Step-by-step explanation:

The opposite sides of a parallelogram are equal.

so,

20x = 15y-2

and consecutive angles are supplementary.

so, 12x+4 +20x =180

or, 32x = 176

or, x = 176/32

x = 5.5

15y-2 = 20x

or, 15y= 20×5.5 + 2

or, 15y = 112

or, y= 112/15

y= 7.46666

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Murrr4er [49]

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3 years ago

Read 2 more answers

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r-ruslan [8.4K]

For the first one:
2x + 2 = 3x - 52
2x + 2 + 52 = 3x - 52 + 52
2x + 54 = 3x
2x - 2x + 54 = 3x -2x
54 = x
For the second:
124 + 2x + 4 = 180
124 + 4 + 2x = 180
128 + 2x = 180
128 - 128 + 2x = 180 - 128
2x = 52
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4 years ago

Write the equation of the line that is parallel to y=2x+6 and passes through the point (1,5)

Vikki [24]

Y - 5 = 2( x - 1 ) <=>
y - 5 = 2x - 2 <=.
2x - y + 3 = 0.

3 0

4 years ago

Call an integer $n$ oddly powerful if there exist positive integers $a$ and $b$, where $b>1$, $b$ is odd, and $a^b = n$. How

azamat

Answer:

There are 16 oddly powerful integers less than 2010

Step-by-step explanation:

∵ b is an odd integer

∵ b > 1

∴ The first value of b is 3

∵ a is an integer

- We can use a = 1, 2, 3, ..........

∵ $a^{b}=n$

∵ n < 2010

- Let a = 1, 2, ............... 12 because 12³ is greatest integer < 2010

∵ 1³ = 1, 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125, 6³ = 216, 7³ = 343,

8³ = 512, 9³ = 729, 10³ = 1000, 11³ = 1331, 12³ = 1728

∴ There are 12 oddly powerful integers with b = 3

Now the second value of b is 5

$1^{5}=1$ but we took 1 before so we will start with 2

∵ $2^{5}=32$ , $3^{5}=243$ , $4^{5}=1024$

- $4^{5}$ is the greatest integer < 2010

∴ There are 3 oddly powerful integers with b = 5

Now the third value of b is 7

∵ $2^{7}=128$

- $2^{7}$ is the greatest integer < 2010

∴ There is 1 oddly powerful integers with b = 7

Now the fourth value of b is 9

∵ $2^{9}=512$

- $2^{9}$ is the greatest integer < 2010

- But we used 512 before

∴ There is no oddly powerful integers with b = 9

- 9 is the greatest value of b which makes $a^{b}$

∵ 12 + 3 + 1 = 16

∴ There are 16 oddly powerful integers less than 2010

5 0

3 years ago

Determine the mode(s) of the data 2, 2, 2, 3, 5, 5, 6, 7, 8, 8, 8, 9, 10.

sergij07 [2.7K]

Answer:

all here

2,2,2, and 8,8,8,

Step-by-step explanation:

its the highest occurrence

7 0

3 years ago