Answer:
2√11
Step-by-step explanation:
The square of the hypotenuse (h) of the smaller triangle is given by the Pythagorean theorem:
h² = 6² +8² = 100
The length of x is given by that same theorem:
h² +x² = 12²
x² = 12² -h² = 144 -100 = 44 . . . . . subtract h², fill in its value
x = √44 . . . . . . . . take the square root
x = 2√11 . . . . . . . simplify the root
Answer:
So W is going to stand for width and L is going to stand for length.
L= 2W+6
78=2L + 2W
Those are the two equations you will use. So plug in L=2W+6 into the other one and solve.
78= 4W+12 +2W
(simplify)
78=6W+12
(-12 from both sides)
66=6W
(divide by 11)
W=11
Replug W into your equation to find L.
L=22+6
(simplify)
L=28
I hope this is right
Step-by-step explanation:
Answer:
44
Step-by-step explanation:
substitute x = 4 and y = 12 into the expression
5x² - 3y
= 5(4)² - 3(12)
= 5(16) - 36
= 80 - 36
= 44
<span>f(x)=3-2x
</span><span>f(8)=3-2(8) = 3 -16 = -13
</span><span>g(x)=1/x+5
</span><span>g(8)=1/8+5 = 1/8 + 40/8 = 41/8
</span><span>[f/g](8) = -13 / (41/8) = -13 * (8/41) = -104/41 = -2 22/41</span>
ΔQTR and ΔSTP are similar triangles. The corresponding sides of similar triangles are the same length.
TR = PT
TS = QT
Input the algebraic expression to make an equation system
PT = TR
y = 2x - 1 <em>(first equation)</em>
TS = QT
6x + 13 = 5y
6x - 5y = -13 <span><em>(second equation)</em>
</span>Using subtitution method, subtitute y with 2x - 1 from first equation into the second equation, to find the value of x
6x - 5y = -13
6x - 5(2x - 1) = 13
6x - 10x + 5 = 13
-4x + 5 = 13
-4x = 13 - 5
-4x = 8
x = 8/-4
x = -2
Find y with subtituting x with -2 in the first equation
y = 2x - 1
y = 2(-2) - 1
y = -4 - 1
y = -5
Answer:
x = -2
y = -5
