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jonny [76]
3 years ago
12

Camille shaded _1 8

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

you are saying it wrong its 1\8 and 3\3

Step-by-step explanation:

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It cost Jodi $44.88 to buy 12 gallons of gas. What was the cost per gallon of gas?
kolbaska11 [484]

Answer: just divide 44.88 by 12 so you will get 3.74

Step-by-step explanation:

7 0
3 years ago
Does anyone know this ? i'm stuck.. i'll give you brainliest and 15 points !! show work.
madam [21]

Answer:

x = 7

Step-by-step explanation:

The angle adjacent to the 70 degree angle is also 70 degrees.  We assume that there are four 90-degree angles in the center of the figure.  Thus, 8x - 36 + 70 + 90 = 180 (the sum of the interior angles is 180 degrees).

Solving  8x - 36 + 70 + 90 = 180 for x:

              8x - 36 = 20, or 8x = 56.

Dividing both sides by 8 yields x = 7.

5 0
3 years ago
The improper fraction 9/8 equals what mixed number ​
Lana71 [14]
The answers is 1 1/8
4 0
4 years ago
Please answer this correctly
Klio2033 [76]

Answer:

x =1

Step-by-step explanation:

Assuming the figures are similar, we can use ratios to solve

x        2

---- = -----

4         8

Using cross products

8x = 2*4

8x = 8

Divide by 8

8x/8 = 8/8

x=1

6 0
3 years ago
PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0
2 years ago
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