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monitta
2 years ago
11

A triangle has side lengths of 17 inches, 19 inches, and 10 inches. What kind of triangle is it?

Mathematics
1 answer:
Virty [35]2 years ago
8 0

Answer:

Scalene triangle

Step-by-step explanation:

a scalene triangle has 3 uneven sides

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A van travels from Town A to Town B. It uses 1 gallon of gas for every 24 miles traveled. A) How many gallons of gas does the va
Setler79 [48]

Answer:

A)  \frac{x}{8} gallons

B)  Distance between Town A and Town B is 48y  miles


Step-by-step explanation:

A)

We know, number of gallons = \frac{DistanceTravelled}{MilesPerGallon}

if miles per gallon (mpg) is given as 24 & total distance travelled is 3x miles, then, using formula we have:

Number of Gallons = \frac{DistanceTravelled}{MilesPerGallon}=\frac{3x}{24}=\frac{x}{8}


B)

Now, given is number of gallons = 2y & we know mpg is 24; <em>so what is the distance?</em>

We use the same formula and solve for distance (let distance between A and B be "D"):

NumberOfGallons=\frac{DistanceTravelled}{MilesPerGallon}\\2y=\frac{D}{24}\\D=2y*24\\D=48y

7 0
2 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Serggg [28]

Answer:

dont know

Step-by-step explanation:

4 0
3 years ago
BRAINLIEST ASAP!!!!
ivanzaharov [21]
The graph of a quadratic equation is a U-shaped curved called parabola. It is because the parabola makes very easy to find the axis of symmetry to plot selected points and finding the roots and vertex.

Good luck :)
4 0
3 years ago
Find the area of the trapezoid.
bija089 [108]
The answer is 27 cm squared
8 0
3 years ago
If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
2 years ago
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