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2 years ago

7

0540-0058= ??? In military time

1 answer:

Tatiana [17]2 years ago

3 0

Answer:

0442 (4:42 normal time)

btw plz give brainliest

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How do you determine the quadratic equation having roots that are real numbers and equal

zvonat [6]

Answer:

To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to calculate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.

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3 years ago

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(3x-22)+ (4y-x-10) <br> Solve for Y

const2013 [10]

answer

Step-by-step explanation:

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3 years ago

The square root of 8 to the 3rd power

zlopas [31]

It’s might b 24 hopefully this helps u

7 0

3 years ago

Please just answer. If you fake it, You will be reported.

koban [17]

Answer:

151 in

Step-by-step explanation:

circumference = 2πr

where r = radius

given radius appears to be 24 so r = 24

so we have C = 2πr and r = 24 and we use 3.14 for π

So C = 2(3.14)(24)

==> multiply 2 and 3.14

C = 6.28(24)

==> multiply 6.28 and 24

C = 150.72

The closest answer is 151 so that is the answer

8 0

2 years ago

Find the difference in area between the circle and the square. Click on the answer until the correct answer is showing

antoniya [11.8K]

The difference in area between the circle and the square is $4\pi -8$

Step-by-step explanation:

Step 1: Finding the area of the square

The area of the square = $side ^2$

Here the side of the square = $2\sqrt{2}$

The area of the square = $(2\sqrt{2})^2$

The area of the square = 8 square units...............(1)

Step 2: Finding the area of the circle

To find the area of the circle lets find the diagonal of the square

The diagonal of the square is equal the diameter of the circle

Now the diagonal of the square = $( \sqrt{2})(side)$

Thus substituting the value

The diagonal = $( \sqrt{2})(2 \sqrt{2})$ = 4 units

$\therefore$ Diameter of the circle = 4 units

Now the area of the circle = $\pi r^2$

where r is the radius of the circle

r = $\frac{diameter}{2}$ = $\frac{4}{2}$ = 2 units

Thus the area of the circle = $\pi (2)^2$ = $4 \pi$ square units .....................(2)

Step 3: Finding the difference

Difference = area of the circle - area of the square

From (1) and (2)

Difference = $4\pi - 8$ square units

8 0

3 years ago