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borishaifa [10]

3 years ago

6

The county fair charges $2.50 per ticket for the rides. Henry bought 15 tickets for the rides and spent a total of $55.50 at the

fair. Henry spent his money only on ride tickets and far admission. The price of the fair admission is the same for everyone. Use x to represent the number of tide tickets and y to represent the total cost.
(A) Find the cost of admission to the fair. Explain how you found the cost of admission.
(B) Write a linear equation that can be used to determine the cost for anyone who pays for ride tickets and fair admission.
(C) Explain what the coefficient on x and the constant of your linear equation represent.

1 answer:

san4es73 [151]3 years ago

4 0

Answer:

<em>(A) $18</em>

<em>(B) $y=2.50x+18$ </em>

<em>(C) Coefficient of x-term represents the cost for each ride ticket and constant term represents the cost of admission to the fair.</em>

Step-by-step explanation:

(A)

The county fair charges $2.50 per ticket for the rides and Henry bought 15 tickets for the rides.

So, the total cost of the 15 tickets will be: $(\$2.50*15)= \$37.50$

He spent total $55.50 on ride tickets and fair admission.

So, the cost of admission to the fair will be: $(\$55.50-\$37.50)= \$18$

(B)

If $x$ represents the number of ride tickets and $y$ represents the total cost, then the cost for $x$ number of ride tickets is $\$2.50x$

So, the linear equation that can be used to determine the cost for anyone who pays for ride tickets and fair admission will be: $y= 2.50x+18$

(C)

In the above linear equation, <u>coefficient of x-term is 2.50, which represents the cost for each ride ticket</u>.

And the <u>constant term is 18, which represents the cost of admission to the fair</u>.

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Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

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